Asked Sep 8, 2019
Using the values given in your lab experiment, what is the change in enthalpy in kJ for the neutralization reaction between HCl and NaOH?  Be sure to include the proper sign but no units.
Lab experiment: 
HCl + NaOH -> NaCl + H2O
-166.4 +-469.4 -> -407.1 + -285.9

Expert Answer

Step 1

Equation for determining the change...

-ΣηΔΗ (ωτn)
дн" -2п,АН (робuлs)

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-ΣηΔΗ (ωτn) дн" -2п,АН (робuлs)


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