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vii. u2 − U₁ = Cp (T₂ – T1) viii. f₁(T,p, x₁) = x₁P ix. Y₁P = x₁₁ Pșat; y; is a gas-phase mole fraction and x; is a liquid-phase mole fraction.

vii. u2 − U₁ = Cp (T₂ – T1) viii. f₁(T,p, x₁) = x₁P ix. Y₁P = x₁₁ Pșat; y; is a gas-phase mole fraction and x; is a liquid-phase mole fraction.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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These are thermodynamics problems.

For the following situations, state under what conditions the following equations would apply. Be as specific (but succinct) as possible.

 

vii. U2 viii. f₁(T,p,x₁) = x₁P u1 = Cp(T2 – Ti) ix. Y₁P = x;√;Pșat; y; is a gas-phase mole fraction and ï¿ is a liquid-phase mole fraction. i X. dpsat dT Ah² →v RT² psat
Transcribed Image Text:vii. U2 viii. f₁(T,p,x₁) = x₁P u1 = Cp(T2 – Ti) ix. Y₁P = x;√;Pșat; y; is a gas-phase mole fraction and ï¿ is a liquid-phase mole fraction. i X. dpsat dT Ah² →v RT² psat
i. K = exp[-TE₁ µi (T)] RT ii. K = x²xD 2 XAX iii. 0 = m₁h₁ + m₂h₂ − m3 +Q+W₂ iv. hu+ Pv xį are mole fractions in liquid. v. w— - § Pdv vi. h2 – h1 = Cp(T2 – Ti)
Transcribed Image Text:i. K = exp[-TE₁ µi (T)] RT ii. K = x²xD 2 XAX iii. 0 = m₁h₁ + m₂h₂ − m3 +Q+W₂ iv. hu+ Pv xį are mole fractions in liquid. v. w— - § Pdv vi. h2 – h1 = Cp(T2 – Ti)
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