Line impedanceMiM1TransformerVsVTM3M2Line impedanceпеutralLine impedanceM3Figure 2: Distribution lines equivalent circuit.Figure 1: Low voltage lines exiting the distributiontransformer center.In the given circuit, low voltage lines are seen coming out of a distribution transformerwhose Low Voltage side is star connected. R (QR = 0) phase for M1 line, S (@S = 120)phase for M2 line andT (oT = -120) phase is used for M3 line. The impedances of theloads at the end of the lines are (100 + j25) N and the impedances of the lines (1 + j) N.• Find the capacitor power required for compensation to be made at cos p= 0.984 (p = 10) at the end of the line.• Find line currents after compensation

Given data: Zm=100+j25 ΩZL=1+j ΩVph=230 Vϕ=10o

VR Line impedance Mi M1 Transformer Vs VT M3, M: M2 Line impedance neutral Line impedance M3 Figure 2: Distribution lines equivalent circuit. Figure 1: Low voltage lines exiting the distribution transformer center. In the given circuit, low voltage lines are seen coming out of a distribution transformer whose Low Voltage side is star connected. R (@R = 0) phase for M1 line, S (µS = 120) phase for M2 line andT (øT = -120) phase is used for M3 line. The impedances of the loads at the end ofthe lines are (100 + j25) N and the impedances of the lines (1 + j) N. • Find the capacitor power required for compensation to be made at cos 4= 0.984 (4 = 10) at the end of the line. • Find line currents after compensation

VR Line impedance Mi M1 Transformer Vs VT M3, M: M2 Line impedance neutral Line impedance M3 Figure 2: Distribution lines equivalent circuit. Figure 1: Low voltage lines exiting the distribution transformer center. In the given circuit, low voltage lines are seen coming out of a distribution transformer whose Low Voltage side is star connected. R (@R = 0) phase for M1 line, S (µS = 120) phase for M2 line andT (øT = -120) phase is used for M3 line. The impedances of the loads at the end ofthe lines are (100 + j25) N and the impedances of the lines (1 + j) N. • Find the capacitor power required for compensation to be made at cos 4= 0.984 (4 = 10) at the end of the line. • Find line currents after compensation

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter8: Symmetrical Components

Section: Chapter Questions

Problem 8.6P

See similar textbooks

Similar questions

Consider the single-Line diagram of a power system shown in Figure 3.42 with equipment ratings given: Generator G1: 50MVA,13.2kV,x=0.15p.u. Generator G2: 20MVA,13.8kV,x=0.15p.u. Three-phase -Y transformer T1: 80MVA,13.2/165YkV,X=0.1p.u. Three-phase Y- transformer T2: 40MVA,165Y/13.8kV,X=0.1p.u. Load: 40MVA,0.8PFlagging,operatingat150kV Choose a base of 100 MVA for the system and 132-kV base in the transmission-line circuit. Let the load be modeled as a parallel combination of resistance and inductance. Neglect transformer phase shifts. Draw a per-phase equivalent circuit of the system showing all impedances in per unit.
Figure 3.32 shows the oneline diagram of a three-phase power system. By selecting a common base of 100 MVA and 22 kV on the generator side, draw an impedance diagram showing all impedances including the load impedance in per-unit. The data are given a follows: G:90MVA22kVx=0.18perunitT1:50MVA22/220kVx=0.10perunitT2:40MVA220/11kVx=0.06perunitT3:40MVA22/110kVx=0.064perunitT4:40MVA110/11kVx=0.08perunitM:66.5MVA10.45kVx=0.185perunit Lines I and 2 have series reactances of 48.4 and 65.43, respectively. At bus 4, the three-phase load absorbs 57 MVA at 10.45 kV and 0.6 power factor lagging.
With generator conyention, where the current leaves the positive terminal of the circuit element, if P is positive then positive real power is delivered. (a) False (b) True
PowerWorid Simulator case Problem 3_60 duplicates Example 3.13 except that a resistance term of 0.06 per unit has been added to the transformer and 0.05 per unit to the transmission line. Since the system is no longer lossless, a field showing the real power losses has also been added to the oneline. With the LTC tap fixed at 1.05, plot the real power losses as the phase shift angle is varied from 10 to +10 degrees. What value of phase shift minimizes the system losses?
Consider the single-line diagram of the power system shown in Figure 3.38. Equipment ratings are Generator 1: 1000MVA,18kV,X=0.2perunit Generator 2: 1000MVA,18kV,X=0.2p.u. Synchronous motor 3: 1500MVA,20kV,X=0.2p.u. Three-phase -Y transformers T1,T2,T3,T4,: 1000MVA,500kV,Y/20kV,X=0.1p.u. Three-phase YY transformer T5: 1500MVA,500kV,Y/20kVY,X=0.1p.u. Neglecting resistance, transformer phase shift, and magnetizing reactance, draw the equivalent reactance diagram. Use a base of 100 MA and 500 kV for the 50-ohm line. Determine the per-unit reactances.
Which termination would result to a phase change of 180 degrees at the load if Zo = 100 ohm? a. 50 ohm b. short circuit c. 75 ohm d. all of these What is the purpose of impedance matching? a. maximum return loss b. maximum SWR c. maximum load power d. maximum reflection A short piece of transmission line that may be open or shorted and used for impedance matching purposes. a. converter b. decoder c. stub d. transformer
Refer to the 5-bus data given below. Sbase = 400 MVA, the base voltage is 15.0 kV for buses 1 and 3, and 345 kV for buses 2, 4, 5. Note that 1-5 and 3-4 are 15/345 kV transformers.a) Draw a one-line diagram of the power system.b) Find the elements Y23, Y43, Y11 Y33 of the system bus admittance matrix.
In a 3-phase overhead system, each line is suspended by a string of 3 insulators. The voltage across the top unit (i.e. near the tower) and middle unit are 10 kV and 11 kV respectively. Calculate (i) the ratio of shunt capacitance to self capacitance of each insulator, (ii) the string efficiency and (iii) line voltage
For the single phase system given in the Figure, the following ratings are given. Transformer A-B: 500V/1.5kV, 9.6 kVA, leakage reactance = 5%. Transformer B-C: 1.2kV/120V, 7.2kVA, leakage reactance= 4%. Line B: series impedance = 0.5+3j Ω. Load C: 120V, 6kVA at 0.8 power factor lagging. a) Determine the actual values of the load impedance and the leakage reactance’s of the transformers referred to primary and secondary sides. b) Choosing 1.2kV as the voltage base for circuit B and 10kVA as the system wide kVA base, express all system impedances in per unit. c) What is the appropriate sending-end voltage (Vs) corresponds to the given loading conditions?
3) State the relation between line and phase values of voltage and current for 3-phase STAR connected load .state the equation for active, reactive power consumed by 3-phase load.
Figure shows the one-line diagram of a simple three-bus power system with generation at buses 1 and 3. The voltage at bus 1 is V1 is 1.025 at an angle of 0◦ per unit. Voltage magnitude at bus 3 is fixed at 1.03 pu with a real power generation of 300 MW. A load consisting of 400 MW and 200 MVAr is taken from bus 2. Line impedances are marked in per unit on a 100 MVA base. (a) Construct Ybus matrix for the system in Figure (b) Using Gauss-Seidel method and initial estimate of V2(0) = 1.0 + j0 and V3(0) = 1.03 + j0 and keeping |V3| = 1.03 pu, determine the phasor values of V2 and V3. Perform two iterations.
An electrical lineman is connecting three single-phase transformers in a Y(primary)-Y(secondary) configuration, for power service to a business. Draw the connecting wires necessary between the transformer windings, and between the transformer terminals and the lines: Note: fuses have been omitted from this illustration, for simplicity.