NEED HELP ASAP. PLEASE SHOW THE DETAILED SOLUTION ON THE BOXED PART. SHOW THE INTEGRATION SOLUTION.THANK YOU. Solution:a.) Q = CA,√2ghQ₁ = (0.6) (π) (0.005)2/19.62(1.2)= 0.0229 m3/sQ2 = (0.6) (7) (0.05)2/19.62(1.8)Q2 = 0.028 m3/sQT = Q1 + Q2 = 0.0229 + 0.028QT = 0.051 m3/sch1Adhb.)t₁ = Sh2 CA/2gh-Q2.25dh= 51.²² (2)(0.6) (π)(0.05)^2√19.6h-0.051900= 118.0817 -17t₁= 65.1405 s1.82.25dht₂ = √√₁₁ (2)(0.6) (π)(0.05)^2√19.6h-0.051900= 61.1236 -17t₂ = 8.1824 sT = t₁ + t₂T = 65.1405 +8.1824T = 73.32 s W.S (t=0)13. In Fig. H is shown a tank 1.5 by 1.5m horizontal section and 3m high withtwo orifices (C=0.60) both 10cm in diameter and 60cm apart. (a) Howmuch water must be supplied to the tank to keep it always full? (b) If thissupply is cut off, how longGiven: AT = 2.25m; h = 3m1.5 m by 1.5 mDo1= 10 cm or 0.10mDo2 = 10 cm or 0.10mC=0.60Find: Q₁ =?t=?↑1.20 m0.60 morifice (1)crifice (2)100

Answered: Image /qna-images/answer/3fc257f1-9a49-4f57-8145-450294f5963d.jpg

W.S (t=0) 13. In Fig. H is shown a tank 1.5 by 1.5m horizontal section and 3m high with two orifices (C=0.60) both 10cm in diameter and 60cm apart. (a) How much water must be supplied to the tank to keep it always full? (b) If this supply is cut off, how long Given: AT = 2.25m; h+ = 3m 1.5 m by 1.5 m Do1 = 10 cm or 0.10m Do2 = 10 cm or 0.10m C = 0.60 Find: Q₁ =? t=? T 1.20 m ↓ 0.60 m orifice (1) crifice (2) 100

W.S (t=0) 13. In Fig. H is shown a tank 1.5 by 1.5m horizontal section and 3m high with two orifices (C=0.60) both 10cm in diameter and 60cm apart. (a) How much water must be supplied to the tank to keep it always full? (b) If this supply is cut off, how long Given: AT = 2.25m; h+ = 3m 1.5 m by 1.5 m Do1 = 10 cm or 0.10m Do2 = 10 cm or 0.10m C = 0.60 Find: Q₁ =? t=? T 1.20 m ↓ 0.60 m orifice (1) crifice (2) 100

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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