Water is pumped from che large tank shown in the igure. The loss in the piping is equal to 2V2 - note that this oss is in units of m?/s? = J/kg. 4 m The pump power is Wpur 40,000 Q – 400,000Q³, where Wump is in Watts and Q s in m³/s a.) Determine the flowrate. p.) Determine the pressure increase across the %3D dшnd, Pump ритр Pipe area = 0.01 m? pump ) Determine the flowrate if the loss was the same but the nump is not installed

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Water is pumped from
the large tank shown in the
figure. The loss in the piping is
equal to 2V2 - note that this
loss is in units of m?/s? = J/kg.
4 m
The pump power is Wpump
40,000 Q – 400,000Q3,
where Wump is in Watts and Q
is in m³/s
a.) Determine the flowrate.
b.) Determine the pressure increase across the pump
dшnd,
Fபாடி
ритр
Pipe area =
0.01 m?
c) Determine the flowrate if the loss was the same but the numn is not installed
Transcribed Image Text:Water is pumped from the large tank shown in the figure. The loss in the piping is equal to 2V2 - note that this loss is in units of m?/s? = J/kg. 4 m The pump power is Wpump 40,000 Q – 400,000Q3, where Wump is in Watts and Q is in m³/s a.) Determine the flowrate. b.) Determine the pressure increase across the pump dшnd, Fபாடி ритр Pipe area = 0.01 m? c) Determine the flowrate if the loss was the same but the numn is not installed
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