Water vapor at 100 degrees Celsius is put in contact with ice at 0 degrees Celsius and this mixture eventually results in 45 kg of liquid water at 30 degrees Celsius. A. How many kilograms of ice were part of the mixture?B. How many kilograms of steam were part of the mixture?

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Asked Nov 26, 2019
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Water vapor at 100 degrees Celsius is put in contact with ice at 0 degrees Celsius and this mixture eventually results in 45 kg of liquid water at 30 degrees Celsius. 

A. How many kilograms of ice were part of the mixture?

B. How many kilograms of steam were part of the mixture?

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Expert Answer

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Step 1

a)

The equation from heat transfer is,

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m )=m1+mc^(100-7,) т.(3.33x10')]+[m.(4186)(30-0)]-[m.(2.26х10")]-[m. (4186)(100-30)] m(458580) m (315620)

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Step 2

Again,

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--(2)

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Step 3

Solving equation (1) and (2), t...

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m18.34kg

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