Homework Help is Here – Start Your Trial Now!
Science
Physics
We know that the mass of the bagged lunch is m = 1.40 kg and the mass of the astronaut is M = 67.0 kg. Before the collision, the bagged lunch moves with a velocity of vi = 1.60 m/s in the positive x-direction and the astronaut is at rest relative to the space station with velocity Vi = 0.         MVi + mvi = MVf + mvf to obtain (67.0 kg)(0 m/s) + (1.40 kg)(1.60 m/s) = (67.0 kg)Vf + (1.40 kg)vf. Because vf = Vf, this further simplifies to (67.0 kg)(0 m/s) + (1.40 kg)(1.60 m/s) = (1.40 kg + 67.0 kg)Vf.            What is the velocity of the astronaut after the collision?

We know that the mass of the bagged lunch is m = 1.40 kg and the mass of the astronaut is M = 67.0 kg. Before the collision, the bagged lunch moves with a velocity of vi = 1.60 m/s in the positive x-direction and the astronaut is at rest relative to the space station with velocity Vi = 0.         MVi + mvi = MVf + mvf to obtain (67.0 kg)(0 m/s) + (1.40 kg)(1.60 m/s) = (67.0 kg)Vf + (1.40 kg)vf. Because vf = Vf, this further simplifies to (67.0 kg)(0 m/s) + (1.40 kg)(1.60 m/s) = (1.40 kg + 67.0 kg)Vf.            What is the velocity of the astronaut after the collision?

Physics for Scientists and Engineers, Technology Update (No access codes included)
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter13: Universal Gravitation
Section: Chapter Questions
Problem 13.75AP: Two identical particles, each of mass 1 000 kg, are coasting in free space along the same path, one...
See similar textbooks
icon
Related questions
Topic Video
Question

We know that the mass of the bagged lunch is

m = 1.40 kg

and the mass of the astronaut is

M = 67.0 kg.

Before the collision, the bagged lunch moves with a velocity of

vi = 1.60 m/s

in the positive x-direction and the astronaut is at rest relative to the space station with velocity

Vi = 0.
 
 
 
 
MVi + mvi = MVf + mvf
to obtain
(67.0 kg)(0 m/s) + (1.40 kg)(1.60 m/s) = (67.0 kg)Vf + (1.40 kg)vf.
Because
vf = Vf,
this further simplifies to
(67.0 kg)(0 m/s) + (1.40 kg)(1.60 m/s) = (1.40 kg + 67.0 kg)Vf.
           What is the velocity of the astronaut after the collision?
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Momentum
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Physics for Scientists and Engineers, Technology …
Physics for Scientists and Engineers, Technology …
Physics
ISBN:
9781305116399
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
Classical Dynamics of Particles and Systems
Classical Dynamics of Particles and Systems
Physics
ISBN:
9780534408961
Author:
Stephen T. Thornton, Jerry B. Marion
Publisher:
Cengage Learning
College Physics
College Physics
Physics
ISBN:
9781285737027
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
Physics for Scientists and Engineers: Foundations…
Physics for Scientists and Engineers: Foundations…
Physics
ISBN:
9781133939146
Author:
Katz, Debora M.
Publisher:
Cengage Learning
Modern Physics
Modern Physics
Physics
ISBN:
9781111794378
Author:
Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS