We observe a sequence of independent identical trials with two possible outcomes on each trial, S and F, and with P(S) = success, Y has a negative binomial distribution with parameters r = 6 and p. Suppose that we observe the sixth success on trial number 10. Show that p = is the value that maximizes p. The number of the trial on which we observe the sixth %3D 3 5 P(Y = 10).

MATLAB: An Introduction with Applications
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We observe a sequence of independent identical trials with two possible outcomes on each
trial, S and F, and with P(S) = p. The number of the trial on which we observe the sixth
success, Y has a negative binomial distribution with parameters r = 6 and p. Suppose that we
observe the sixth success on trial number 10. Show that p =
3
is the value that maximizes
P(Y
= 10).
Transcribed Image Text:We observe a sequence of independent identical trials with two possible outcomes on each trial, S and F, and with P(S) = p. The number of the trial on which we observe the sixth success, Y has a negative binomial distribution with parameters r = 6 and p. Suppose that we observe the sixth success on trial number 10. Show that p = 3 is the value that maximizes P(Y = 10).
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