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- The video referenced in the question is https://youtu.be/03zVy3wLLC8I asked this question earlier but I think I forgot to include a conversion wht we know : mm of citrix acid = 192.14g/moldensity of citrix acid =166g/cm3 1 lime = 2tbsp of juice = 6 tsp 1tsp = 4.929x10-3L Q: assume citrix acid makes up 7.96% by volume of the lime juice . How many moles of citrix acid are in the recipe ( calls for 1 lime juice)q 8 a https://cxp.cengage.com/contentservice/assets/owms01h/references/chemtables/gen_chem/eo.html table
- https://cxp.cengage.com/contentservice/assets/owms01h/references/chemtables/genChemIndex.htmlTo identify a liquid substance, a student determined itsdensity. Using a graduated cylinder, she measured out a 45-mLsample of the substance. She then measured the mass of thesample, finding that it weighed 38.5 g. She knew that the substancehad to be either isopropyl alcohol 1density 0.785 g>mL2or toluene 1density 0.866 g>mL2. What are the calculated densityand the probable identity of the substance?22. A 100g of water is mixed to 150g of alcohol (ρ = 0.76 g/cm3). Calculate the resulting density of the solution assuming that it is mixed completely.a. 0.8407g/cm3 b. 0.8379g/cm3 c. 0.8624g/cm3 d. 0.8153g/cm3
- What is the boiling point of the automobile radiator fluid prepared by mixing 1.11 L of ethylene glycol (HOCH2CH2OH, density = 1.114 g/mL) with 1.06 L of water (density = 1.000 g/mL)?The Kb of water is 0.520°C/m.Pheromones are compounds secreted by females of manyinsect species to attract mates. Typically, 1.0 × 10−8gof a pheromone is sufficient to reach all targeted maleswithin a radius of 0.50 mi. Calculate the density of thepheromone (in grams per liter) in a cylindrical air spacehaving a radius of 0.50 mi and a height of 40 ft (volumeof a cylinder of radius r and height h is πr2h).https://cxp.cengage.com/contentservice/assets/owms01h/references/chemtables/gen_chem/eo.html ^ table image:
- Given the following data forMass of test tube, beaker and cyclohexane = 100.17 gMass of test tube and beaker = 84.07 gFreezing point of cyclohexane = 6.59 oCMass of weighing paper + naphthalene =1.080 gMass of weighing paper = 0.928 gFreezing point solution = 5.11oCKf = 20.8oC/mDetermine the followinga. mass of cyclohexane in g (2 decimal places); _____b. mass of naphthalene in g (4 decimal places); _____c. freezing point depression (2 decimal places); _____d. molality of solution (3 significant figures); _____e. moles of naphthalene (3 significant figures); _____f. molar mass of naphthalene, experimentally (3 significant figures); _____g. % error if theoretical molar mass of naphthalene is 128.17 g/ mole, USE ABSOLUTE VALUE (3 significant figure); ____A. B. and C. already solved (https://www.bartleby.com/questions-and-answers/chemistry-question/a89691d6-2162-4677-b0cc-dc84fcceda08). Please answer E, F and GCircle in pencil in the image on th eirght cide of the diagram is a "2"( Pb(NO3)2 ).Why do meltiing, freezing and boiling point varies and depends on a kind of matter? Not less than 6 sentences.