What fraction of their babies will be:

Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
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Author:Michael Cummings
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Chapter11: Genome Alterations: Mutation And Epigenetics
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Quarter horses (for the information of non-gamblers,
these are an actual breed of race horses; not all of the rest of this problem is very actual however) are produced in
a two-stage process. First, a whole horse is cut in half to produce half horses. This requires a functional A gene. If
there is no functional A gene, the horse remains whole. Second, the B gene cuts the half horses into quarter
horses. However, a dominant C gene (C-) will block the action of the B gene, leading to a half horses instead of
quarter horses. See diagram below. These 3 genes are UNLINKED.
A
BIBB| Bb|CCCCc
b[Bbl bb C.ee
A AA Ag
B
Whole horses
→ Half horses
Quarter horses
a Aal aa
An AaBbCc horse was crossed to an AaBbes,horse (both parents have slightly different genotypes!).
What fraction of their babies will be: (Hint: ask yourself what's required for each gene dominant or recessive
then multiply)
a)
whole horses?
b)
quarter horses?
с)
half horses (hint: figure out parts a and b first, and then using those #s, figure out this one.)
Now show how to directly find the half horse amount.
d)
Hints: Find all the nonoverlapping, mutually exclusive ways to be a half horse. What are they? Next, what do you
do with these numbers? If you get the same answer you got in part c, then you probably got it right.
Transcribed Image Text:Quarter horses (for the information of non-gamblers, these are an actual breed of race horses; not all of the rest of this problem is very actual however) are produced in a two-stage process. First, a whole horse is cut in half to produce half horses. This requires a functional A gene. If there is no functional A gene, the horse remains whole. Second, the B gene cuts the half horses into quarter horses. However, a dominant C gene (C-) will block the action of the B gene, leading to a half horses instead of quarter horses. See diagram below. These 3 genes are UNLINKED. A BIBB| Bb|CCCCc b[Bbl bb C.ee A AA Ag B Whole horses → Half horses Quarter horses a Aal aa An AaBbCc horse was crossed to an AaBbes,horse (both parents have slightly different genotypes!). What fraction of their babies will be: (Hint: ask yourself what's required for each gene dominant or recessive then multiply) a) whole horses? b) quarter horses? с) half horses (hint: figure out parts a and b first, and then using those #s, figure out this one.) Now show how to directly find the half horse amount. d) Hints: Find all the nonoverlapping, mutually exclusive ways to be a half horse. What are they? Next, what do you do with these numbers? If you get the same answer you got in part c, then you probably got it right.
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