What is P(A), the probability of event A? O P(A) = 0.36 O P(A) = 0.76 O P(A) = 0.22 O P(A) = 0.32 Let event C be the event that the game ends in a tie. What is P(C), the probability of event C? O P(C) = 0.32 O P(C) = 0.28 O P(C) = 0.50 O P(C) = 0.86 Define event B as the event that roommate B wins the game and not have to wash dishes is the probability roommate B wins the game? O P(B) = 0.39 O P(B) = 0.67 O P(B) = 0.36 O P(B) = 0.43

Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter14: Counting And Probability
Section14.CT: Chapter Test
Problem 2CT: A hospital cafeteria offers a fixed-price lunch consisting of a main course, a dessert, and a drink....
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A common way for two people to settle a frivolous dispute is to play a game of rock-paper-scissors. In this game, each person simultaneously displays
a hand signal to indicate a rock, a piece of paper, or a pair of scissors. Rock beats scissors, scissors beats paper, and paper beats rock. If both players
select the same hand signal, the game results in a tie.
Two roommates, roommate A and roommate B, are expecting company and are arguing over who should have to wash the dishes before the company
arrives. Roommate A suggests a game of rock-paper-scissors to settle the dispute.
Scissors
beats paper
Paper
beats rock
Rock
beats scissors
Consider the game of rock-paper-scissors to be an experiment. In the long run, roommate A chooses rock 21% of the time, and roommate B chooses
rock 61% of the time; roommate A selects paper 39% of the time, and roommate B selects paper 21% of the time; roommate A chooses scissors
40% of the time, and roommate B chooses scissors 18% of the time. (These choices are made randomly and independently of each other.)
The probabilities were assigned using the relative frequency approach
classical approach
Define event A as the event that roommat
bes not have to wash the dishes.
subjective approach
What is P(A), the probability of event A?
relative frequency approach
Transcribed Image Text:A common way for two people to settle a frivolous dispute is to play a game of rock-paper-scissors. In this game, each person simultaneously displays a hand signal to indicate a rock, a piece of paper, or a pair of scissors. Rock beats scissors, scissors beats paper, and paper beats rock. If both players select the same hand signal, the game results in a tie. Two roommates, roommate A and roommate B, are expecting company and are arguing over who should have to wash the dishes before the company arrives. Roommate A suggests a game of rock-paper-scissors to settle the dispute. Scissors beats paper Paper beats rock Rock beats scissors Consider the game of rock-paper-scissors to be an experiment. In the long run, roommate A chooses rock 21% of the time, and roommate B chooses rock 61% of the time; roommate A selects paper 39% of the time, and roommate B selects paper 21% of the time; roommate A chooses scissors 40% of the time, and roommate B chooses scissors 18% of the time. (These choices are made randomly and independently of each other.) The probabilities were assigned using the relative frequency approach classical approach Define event A as the event that roommat bes not have to wash the dishes. subjective approach What is P(A), the probability of event A? relative frequency approach
What is P(A), the probability of event A?
O P(A) = 0.36
O P(A) = 0.76
O P(A) = 0.22
O P(A) = 0.32
Let event C be the event that the game ends in a tie.
What is P(C), the probability of event C?
O P(C) = 0.32
O P(C) = 0.28
O P(C) = 0.50
O P(C) = 0.86
Define event B as the event that roommate B wins the game and thus does not have to wash the dishes. What is the probability that roommate B wins
the game?
O P(B) = 0.39
O P(B) = 0.67
O P(B) = 0.36
O P(B) = 0.43
Transcribed Image Text:What is P(A), the probability of event A? O P(A) = 0.36 O P(A) = 0.76 O P(A) = 0.22 O P(A) = 0.32 Let event C be the event that the game ends in a tie. What is P(C), the probability of event C? O P(C) = 0.32 O P(C) = 0.28 O P(C) = 0.50 O P(C) = 0.86 Define event B as the event that roommate B wins the game and thus does not have to wash the dishes. What is the probability that roommate B wins the game? O P(B) = 0.39 O P(B) = 0.67 O P(B) = 0.36 O P(B) = 0.43
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