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What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Pb2+ concentration is 7.14×10-4 M and the Mg2+ concentration is 1.35 M? Pb2+(aq) + Mg(s) Pb(s) + Mg2+(aq) Answer:  V The cell reaction as written

What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Pb2+ concentration is 7.14×10-4 M and the Mg2+ concentration is 1.35 M? Pb2+(aq) + Mg(s) Pb(s) + Mg2+(aq) Answer:  V The cell reaction as written

Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter20: Electrochemistry
Section20.1: Voltaic Cells
Problem 13SSC
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What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Pb2+ concentration is 7.14×10-4 M and the Mg2+ concentration is 1.35 M?

Pb2+(aq) + Mg(s) Pb(s) + Mg2+(aq)

Answer:  V

The cell reaction as written above is spontaneous for the concentrations given: 

What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Pb²* concentration is 7.14x104 M and the Mg²* concentration is 1.35 M? Pb2*(aq) + Mg(s)–→ Pb(s) + Mg²*(aq) Answer: The cell reaction as written above is spontaneous for the concentrations given:
Transcribed Image Text:What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Pb²* concentration is 7.14x104 M and the Mg²* concentration is 1.35 M? Pb2*(aq) + Mg(s)–→ Pb(s) + Mg²*(aq) Answer: The cell reaction as written above is spontaneous for the concentrations given:
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