What is the disintegration energy (in MeV) of the spontaneous decay: 116Nd → Ce + He -> 58 Knowing that: 19 mNd = 143.910087 u. mce = 139.905439 u. mHe = 4.002603 u and 1u = 1.67 x 10-27 Kg.

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Chapter31: Radioactivity And Nuclear Physics
Section: Chapter Questions
Problem 40PE: (a) Write the complete + decay equation for llC. (b) Calculate the energy released in the decay....
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What is the disintegration energy (in MeV) of the spontaneous decay:
116Nd → Ce + He
->
58
Knowing that:
19
mNd = 143.910087 u.
mce
= 139.905439 u.
mHe
= 4.002603 u
and
1u = 1.67 x 10-27 Kg.
Transcribed Image Text:What is the disintegration energy (in MeV) of the spontaneous decay: 116Nd → Ce + He -> 58 Knowing that: 19 mNd = 143.910087 u. mce = 139.905439 u. mHe = 4.002603 u and 1u = 1.67 x 10-27 Kg.
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