What is the equilibrium-constant expression of the basic dissociation of NaNO2?         Kb = [OH-]/([HNO2] [NO2])     Kb = ([NO2] [OH-])/[HNO2]       Kb = ([HNO2] [OH-])/[NO2]        Kb = ([HNO2] [NO2])/[OH-]

World of Chemistry, 3rd edition
3rd Edition
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Chapter16: Acids And Bases
Section: Chapter Questions
Problem 5A
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What is the equilibrium-constant expression of the basic dissociation of NaNO2?

 

 

   

Kb = [OH-]/([HNO2] [NO2])

   

Kb = ([NO2] [OH-])/[HNO2]

 

   

Kb = ([HNO2] [OH-])/[NO2]

 

   

 Kb = ([HNO2] [NO2])/[OH-]

 

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