What is the first variable to enter in the stepwise regression? [Select] How many variables entered in the entire process? [Select] What do you notice about R2 when you increase the number of variables? [Select]
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- The solid black line in the figure below shows data from Vienna, which started requiring face masks on April 6, 2020. The dashed black line plots data from a nearby Salzburg, that did not implement a face mask requirement. Based on the data in the figure, estimate the impact of face masks on the cumulative number of Covid-19 cases in Vienna? Express your answer as a percent.A paper† gave data on x = change in Body Mass Index (BMI in kilograms/meter2) and y = change in a measure of depression for patients suffering from depression who participated in a pulmonary rehabilitation program. JMP output for these data is shown below. A scatterplot titled "Bivariate Fit of Depression Score Schange by BMI Change" has 12 points and a line plotted on it. The horizontal axis is labeled "BMI change" and ranges from about −0.8 to about 1.8. The vertical axis is labeled "Depression score change" and ranges from about −2 to 20. The points are plotted from left to right in an upward, diagonal direction starting from the middle left of the diagram. The points are very scattered and are between approximately −0.5 to 1.5 on the horizontal axis and between approximately −1 to 18 on the vertical axis. A line with positive slope titled "Linear Fit" is drawn across the plot to approximate the trend of the points. The line enters the viewing window at about (−0.8, 3) and exits at…A Miraculin—a protein naturally produced in a rare tropical fruit—can convert a sour taste into a sweet taste. Consequently, miraculin has the potential to be an alternative low-calorie sweetener. In Plant Science (May 2010), a group of Japanese environmental scientists investigated the ability of a hybrid tomato plant to produce miraculin. For a particular generation of the tomato plant, the amount x of miraculin produced (measured in micrograms per gram of fresh weight) had a mean of 105.3 and a standard deviation of 8.0. Assume that x is normally distributed. (a) Find P(x >120).
- Data from the Motor Vehicle Department indicate that 80% of all licensed drivers are older than age 25. Information on the age of n = 50 people who recently received speeding tickets was sourced by researchers who are interested in whether the age distribution for the sample of drivers who recently received speeding tickets is different from the age distribution for the population of licensed drivers. Proposed analysis and why you chose the analysis: Measurement type (i.e., nominal, ordinal, continuous) for variable(s) that will be used in the analysis: Null and alternative hypotheses (based on context of study) in symbols: Inferential statistic(s) and p-value(s): Decision: Conclusion: Based on your decision, identify and explain the type of error you could be making with respect to the conclusions of the studyData from the Motor Vehicle Department indicate that 80% of all licensed drivers are older than age 25. Information on the age of n = 50 people who recently received speeding tickets was sourced by researchers who are interested in whether the age distribution for the sample of drivers who recently received speeding tickets is different from the age distribution for the population of licensed drivers. Proposed analysis and why you chose the analysis: Measurement type (i.e., nominal, ordinal, continuous) for variable(s) that will be used in the analysis: Null and alternative hypotheses (based on context of study) in symbols: Test assumptions and make a decision (please provide written evidence to support your decision): Inferential statistic(s) and p-value(s): Decision: Conclusion: Based on your decision, identify and explain the type of error you could be making with respect to the conclusions of the study:Scores on a certain test are normally distributed with a variance of 70. A researcher wishes to estimate the mean score achieved by all adults on the test. Find the sample size needed to assure with 95 percent cinfidence that the sample mean will not differ from the population mean by more than 2 units. Show work.
- Accumulation of mercury (Hg) in fish is hypothesized to correlate with the fish size. Barbonymus schwanenfeldii is a species commonly found in a dam in Sarawak. Table 1 shows data of Hg concentration (mg/kg) present in three sizes of fish caught in the dam in triplicates.The parameter “∆uv” helps to determine the colour balance of LiquidCrystal Display (LCD) panels on a manufacturing line. The targetvalue, upper and lower specification limits for the product are ∆uv =0.0000, ∆uv = 0.0200 and ∆uv = –0.0200 respectively, where ∆uv is aunitless parameter.Prior knowledge of the process provides evidence that ∆uv variesrandomly. Recent measurements at final test indicate that the meanvalue of ∆uv is –0.0027 and the standard deviation is 0.0057. 100,000 units of that LCD panel are produced, Calculate the number of panels that falls below, and the number of panels that falls above, the specification limitsThe key assumptions of the ANOVA include homogeneity of variance, normality of population distributions and: Independence of observations Variability of residuals The IV must be measured on a continuous level The DV must be measured on a nominal level
- The random variable of number of pages in your textbook would be classified as: continuous data discrete data (Dont hand writing solution)A process has a process capability index of Cp = 1.2. a) Assume the process mean is set to its optimal value. Express the upper and lower specification limits in terms of the process mean and standard deviation. b) Using the normal curve, estimate the proportion of units that will be nonconforming. c) Is it likely or unlikely that the true proportion of nonconforming units will be quite different from the estimate in part (b)? Explain.A certain polymer is used for evacuation systems for aircraft. It is important that the polymer be resistant tothe aging process. Fifty specimens of the polymer were used in an experiment. Twenty‐five were assignedrandomly to be exposed to an accelerated batch aging process that involved exposure to high temperatures for10 days. Question Which Treatment results in the higher mean tensile strength? (Circle One) Aging or No AgingWhich Treatment has the higher variability? (Circle One) Aging or No Aging