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- interpret NMR spectra and report NMR data stating, in this order: nucleus (1H or 13C), solvent, machine frequency, peaks in order from high to low chemical shift including multiplicity, coupling constants and integrationMS: m/z=148 (M,100%),149 (11%) IR (liquid film): 3077‐2835 (multitude of weak peaks) 1640(m),1611(m),1511(s),1301(m),1247(s),1176(s),1038(s),922(m),914(m) and 810(m)cm^-1 There are no absorptions in the 3100-‐4000cm^-1 region of the spectrum. (m=medium absorption, s=strong absorption). Choose (circle) the best structure for estragole (W) from the four possible structures (1-4)shown below. Explain briefly how you eliminated each of the incorrect structures for W.NMR of profuct is C5H12O2. Solve for the starting material or product and then fill in the missing componenet to give overall reaction. Use one of this reactions I) CH3OH/H2SO4 2) 1. BH3. 2. H2O2, OH,H20 3) 1. OSO4. 2. NaHSO3 4) H3O+ 5)1. Hg(OAc)2, CH3OH. 2. NaBH4 6) Br2 in CCL4 7) Br2 in CH3OH 8)Br2 in CH3OH 9) Cl2 in H2O Show reaction mechanism
- I have problems understanding the results of this experiment, could you help me by explaining the results? Spectrophotometric of a Cobalt Chloride Solution Analysis Table 1 Absorption Spectrum of Cobalt Chloride Using a Spectrophotometer Wavelength Absorbance 400 410 420 430 440 450 460 370 480 490 500 510 520 530 540 550 560 570 580 590 600 610 620 630 640 650 660 670 680 690 700 0.036 0.044 0.063 0.095 0.147 0.215 0.284 0.329 0.362 0.402 0.450 0.479 0.464 0.398 0.314 0.216 0.142 0.087 0.054 0.041 0.036 0.036 0.034 0.028 0.030 0.023 0.023 0.023 0.014 0.014 0.011 ]I have an NMR spectrum. There are 5 peaks. There is a doublet at 9.6 ppm (integrates to 2H) where aldehydes usually arise, don't know why there is a doublet. There is another doublet at 6.8 ppm, again integrating to 2H. There is a singlet at 4.5 ppm, integrating to 1H. There is a quartet at 3.4 ppm integrating to 2H, and lastly there is triplet at 1.2 ppm integrating to 3H. i recofnize the ethyl group but don't understand the peak at 9.6 unless it is not an aldehyde.1. For each set of spectral data, propose an acceptable structure that is consistent with the data. a. MS: M+ m/z=71, IR: 3340, 2960, 2870 cm-1 , 13C NMR: 47.20 (CH2), 25.64 (CH2) ppm b. MS: M+ m/z= 102, IR: 2960, 2870 cm-1, 13C NMR: 72.73 (t), 23.20 (t), 10.80 (q) ppm c. MS: M+ m/z=74, IR: 3310, 2960, 2870 cm^-1, 13C NMR: 62.44 (down), 34.86 (down), 18.98 (down), 13.88 (up) ppm (DEPT-direction) d. MS: M+ m/z=92 (M:M+2=3:1), IR: 2960, 2870 cm^-1, 13C NMR: 67.29 (C), 34.46 (CH3) ppm e. MS:M+ m/z=70, IR: 3070, 2960, 2870, 1666 cm^-1, 13C NMR: 138.92 (t), 114.26 (d), 35.96 (t), 22.17 (t), 13.59 (q) ppm f. MS: M+ m/z= 72, IR: 2960, 2870 cm^-1, 13C NMR: 31.68 (t), 29.80 (d), 22.20 (q), 11.69 (q) ppm g. MS: M+ m/z= 84, IR: 2960, 2870, 1734 cm^-1, 13C NMR: 220.16 (C), 38.30 (CH2), 23.24 (CH2) ppm h. MS:M+ m/z= 138, (M:M+2=1:1), IR: ~3010(broad), 1715 cm^-1, 13C NMR: 173.61(s), 25.21(t) ppm i. MS:M+ m/z=88, IR: 2960, 2870, 1736cm^-1, 13C NMR: 170.95 (C), 60.34 (CH2), 20.98 (CH3), 14.23 (CH3)…
- Please help me analyze this 1H and 13C Acetylferrocene NMR data. I am not sure how to read the peaks and what information they give.a. An oxygen-containing compound shows an absorption band at ~1700 cm-1 and no absorption bands at ~3300 cm-1, ~2700 cm-1, or ~1100 cm-1. What class of compound is it? b. A nitrogen-containing compound shows no absorption band at ~3400 cm-1 and no absorption bands between ~1700 cm-1 and ~1600 cm-1 or between 2260 cm-1 and 2220 cm-1. What class of compound is it?The 1H NMR spectrum of methylbenzene (C6H5CH3) recorded on a 500 Mhz spectrometer consists of signals at chemical shifts of 2.21 parts per million and 7.10 ppm. calculate the frequency, downfield of TMS, of each absorption.
- provide major products in box 13 cnmr spec at 20 24 54 ir spec strong peak 1738Imine compounds usually show stretching bands in the IR in the range of 1690-1649cm-1 and aromatic amines show a C-N stretch at 1340-1265cm-1. A related compound, N-benzylideneaniline, does not show tautomerism and has a C-N stretch at 1678cm-1 while H2SB-1(2-(2-hydroxybenzylideneamino)phenol ) shows a C-N stretch of 1590 cm-1. Given this information, does H2SB-1 show some C-N single bond character.The NMR spectra for compound 1 were acquired in a 7.5 mg / 0.6 mL solution ofCDCl3 and are found in the accompanying file. The 1H are also listedbelow. Identify the name of compound 1 and Provide a full analysis of the NMR spectra for compound 1 with table showing peak name and assignment 1H NMR (400 MHz, CDCl3) δ 7.73 (d, J = 9.5 Hz, 1H), 7.56 (ddd, J = 8.5, 7.5, 1.6 Hz, 1H),7.51 (dd, J = 7.5, 1.6 Hz, 1H), 7.36 (d, J = 8.5 Hz, 1H), 7.30 (dd, J = 8.5, 7.5 Hz, 1H), 6.45(d, J = 9.5 Hz, 1H).