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- A force F1, of magnitude 6.00 units acts on an object at the origin in a direction = 30.0 above the positive x-axis (Fig. P3.8). A second force F2 of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F1 + F2?. Figure P3.8Three forces act on an object, given by?⃗ = 33.3 ? in the direction 35° north of east?⃗⃗ = 42.5 ? in the direction 55° west of north?⃗ = 52.6 ? in the direction 15° east of south (Assume east and north are directed along the +x-axis and +y-axis, respectively.) Find the resulting force (magnitude and direction).Three concurrent forces are pulling the box, the first one pulls 5 N, North; second pulls 5N, South and and the third one pulls 8 N, East. What is the magnitude and direction of their resultant force? a. 18 N, East b. 8 N, West c. 8 N, East d. 3N, West
- Find the resultant of the following forces by component method: F1 =12N,south; F2 =24N, 30° north of west; F3 = 15N, 75° south of west; and F4 = 32 N, 50° south of east.If the magnitudes f1 and f2 are both equal to 4newtons, what are the horizontal and vertical components of the two forces? F1x=?F1y=?F2x=?F2y=?There are two forces on the 2.00 kg box in the overhead view of but only one is shown. For F1 = 20.0N,a =12.0 m/s^2and θ= 30.0 degree find the second force (a) in unit-vector notation and as (b) a magnitude and (c) an angle relative to the positive direction of the x axis.
- The resultant of four coplanar, concurrent forces is 600 lb, directed S 40oE. Three of the forces are 500 lb, directed NW,; 400 lb, directed E; and 300 lb directed S. What is the x-component of the fourth force? What is the y-component of the fourth force? What are the magnitude and direction of the fourth force?An antelope is being pulled by two forces whose vector-component expressions are: F1 = -6Ni + -9.1Nj + -8.6Nk F2 = 4.9Ni + 1.6Nj + -0.4Nk What is the angle (in degrees) between these two vectors?At one moment during a walk around the block, there are four forces exerted upon Fido - a 10.0 kg dog. The forces are: Fapp = 67.0 N at 30.0° above the horizontal (rightward and upward)Fnorm = 64.5 N, upFfrict = 27.6 N, leftFgrav = 98 N, down Resolve the applied force (Fapp) into horizontal and vertical components, then add the forces up as vectors to determine the net force.
- An antelopebis being pulled by two forces whose vector-component expressions are: F1: -3.3Ni + 4.5 Nj + -2.7Nk F2: -1Ni + 0.2 Nj + 3.4 Nk What is the angle (in degrees) between these two vectors?A force of magnitude 7.50 N pushes three boxes with masses m1=1.30kg ,m2=3.20kg, and m3=4.90kg. Find the magnitude of the contact force between boxes 1 and 2.There are two forces on the 1.19 kg box in the overhead view of the figure but only one is shown. For F1 = 15.7 N, a = 14.7 m/s2, and θ = 34.1°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.)