Question
Asked Oct 26, 2019

What is the maximum mass of S8S8 that can be produced by combining 88.0 g88.0 g of each reactant?

 

8SO2+16H2S⟶3S8+16H2O

 

mass of S8:
 
check_circleExpert Solution
Step 1

According to the given chemical reaction, S8 molecules are produced when SO2 reacts with H2S.

The mass of both reactants is 88 g each.

The molecular mass of SO2 =64.066 g mol-1

The molecular mass of H2S = 34.1 g mol-1

Since no.of mole is given mass per molecular mass.

So no. of mole (n) of SO2 -:

No. of moles of H2S -:

8 So2+16 H2S3 sg+16 H20
-(1)
88 g
64.066 gmol
n 1.3735 mol
88 g
n=
mol-
34.1
n 2.5806 mol
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8 So2+16 H2S3 sg+16 H20 -(1) 88 g 64.066 gmol n 1.3735 mol 88 g n= mol- 34.1 n 2.5806 mol

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Step 2

According to given equation (1), the stoichiometric ratio of SO2 and H2S is 1:2, which means 1 mole of  SO2 reacts with 2moles of H2S.

But from our calculation 1.3735 moles of SO2 reacts with 2.5806 moles of  H2S.

Converting it into simple rat...

SO.
1.3735
HS 2.5806
1.3735
1.3735
H S 2.5806
1.3735
1
1.8788
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Image Transcriptionclose

SO. 1.3735 HS 2.5806 1.3735 1.3735 H S 2.5806 1.3735 1 1.8788

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