What is the pH at exactly 1/2 of the volume required to reach the equivalence point in the titration of (4.510x10^1) mL of (4.66x10^-1) M HCN with (6.9500x10^-1) M КОН? Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer:

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter15: Complex Acid/base Systems
Section: Chapter Questions
Problem 15.29QAP
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What is the pH at exactly 1/2 of the volume required to reach the equivalence point
in the titration of (4.510x10^1) mL of (4.66x10^-1) M HCN with (6.9500x10^-1) M
КОН?
Enter your answer in scientific notation with 3 sig figs. Do not include any units in
your answer.
Do not round any intermediate calculations.
Note: Your answer is assumed to be reduced to the highest power possible.
Your Answer:
х10
Answer
Transcribed Image Text:What is the pH at exactly 1/2 of the volume required to reach the equivalence point in the titration of (4.510x10^1) mL of (4.66x10^-1) M HCN with (6.9500x10^-1) M КОН? Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: х10 Answer
How many mL of (6.22x10^-1) M HCOOH would it take to reach the equivalence
point in the titration of (4.5900x10^1) mL of (4.680x10^-1) M KOH?
Enter your answer in scientific notation with 3 sig figs. Do not include any units in
your answer.
Do not round any intermediate calculations.
Note: Your answer is assumed to be reduced to the highest power possible.
Your Answer:
x10
Answer
Transcribed Image Text:How many mL of (6.22x10^-1) M HCOOH would it take to reach the equivalence point in the titration of (4.5900x10^1) mL of (4.680x10^-1) M KOH? Enter your answer in scientific notation with 3 sig figs. Do not include any units in your answer. Do not round any intermediate calculations. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 Answer
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