What is the pH of a buffer prepared by mixing 100 mL 0.050 mM NaH2PO4 and 25 mL 0.075 mM Na2HPO4? (pKa1=2.2; pKa2= 7.21; pKa3=12.7) Please show step by step solution.

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A: The chemical reaction given is 

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A: The answer is as follows:  

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A: The solution is as follows:  

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A: Volume of solution = 2 ml = 0.002 l Molarity of solution =0.00400 M

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A: The correct option is as follows:  

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A: Answer: This question is based on acid-base titration where acid is being titrated against base.

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A: Freezing point depression = i × m × Kf

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Q: . Convert 45000 mg/L of NaCl to molar concentration of NaCI. AW Na = 23 ; CI = 35.45

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Q: concentration

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.