What is the rate law for this process? Step 1: NO2(g) --> NO(g) + O(g) slow Step 2: O2(g) + O(g) --> 03(g) fast Rate = k[NO2] Rate = k[NO2][O2]/[NO] Rate = k Rate = k[NO2]? Rate = k[NO2][O2][O] Rate = k[O]°[NO] Rate = k[O2][O] %3D

Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter12: Kinetics
Section: Chapter Questions
Problem 1E: What is the difference between average rate, initial rate, and instantaneous rate?
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What is the rate law for this process?
Step 1: NO2(g) --> NO(g) + O(g)
slow
Step 2: O2(g) + O(g) --> 03(g)
fast
Rate = k[NO2]
Rate = k[NO2][O2]/[NO]
Rate = k
Rate = k[NO2]?
Rate = k[NO2][O2][O]
Rate = k[O]°[NO]
Rate = k[O2][O]
Transcribed Image Text:What is the rate law for this process? Step 1: NO2(g) --> NO(g) + O(g) slow Step 2: O2(g) + O(g) --> 03(g) fast Rate = k[NO2] Rate = k[NO2][O2]/[NO] Rate = k Rate = k[NO2]? Rate = k[NO2][O2][O] Rate = k[O]°[NO] Rate = k[O2][O]
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