8) For the reaction 2N2O5 (g) → 4NO2 (g) + O2 (g), the following data was collected. The integrated rate law for this reaction is: In [N2O5] = - (0.0301s"!) t+ In [N2O5]o t (seconds) [N2Os] (M) 1.24 x 10-2 0.92 x10-2 0.68 x 10-2 0.50 x 10-2 0.37 x 10-2 0.28 x 10-² 0.15 x 102 10. 20. 30. 40. 50. 70. (First order) b) What is the value of the rate constant? (

Chemistry: An Atoms First Approach
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Chapter11: Chemical Kinetics
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Problem 6ALQ: For the reaction A + B C, explain at least two ways in which the rate law could be zero order in...
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8) For the reaction 2N2O5 (g) → 4NO2 (g) + O2 (g), the following data was collected.
The integrated rate law for this reaction is: In [N2O5] = - (0.0301s') t + In [N2Os]o
t (seconds)
[N2O5] (M)
1.24 x 10-2
0.92 x10-2
0.68 x 10-2
0.50 x 10-²
0.37 x 10-2
0.28 x 10-²
0.15 x 10 ²
10.
20.
30.
X
40.
50.
70.
(First order)
b) What is the value of the rate constant? (
Transcribed Image Text:8) For the reaction 2N2O5 (g) → 4NO2 (g) + O2 (g), the following data was collected. The integrated rate law for this reaction is: In [N2O5] = - (0.0301s') t + In [N2Os]o t (seconds) [N2O5] (M) 1.24 x 10-2 0.92 x10-2 0.68 x 10-2 0.50 x 10-² 0.37 x 10-2 0.28 x 10-² 0.15 x 10 ² 10. 20. 30. X 40. 50. 70. (First order) b) What is the value of the rate constant? (
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