What is the rate law of the reaction                         NO2(g)    +    CO(g)   ó   NO(g)   +   CO2(g)       If the mechanism behind it is : 2NO2(g) à   2NO(g)   +   O2(g)          (slow) NO(g) +   CO(g)   +   O2(g)   à   NO2(g)   +   CO2(g)       (fast)   Rate of reaction is rate of slow step.   Rate = k [NO2]2

Chemistry: Matter and Change
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ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
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Chapter16: Reaction Rates
Section: Chapter Questions
Problem 70A
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  • What is the rate law of the reaction

                        NO2(g)    +    CO(g)   ó   NO(g)   +   CO2(g)      

If the mechanism behind it is :

  • 2NO2(g) à   2NO(g)   +   O2(g)          (slow)
  • NO(g) +   CO(g)   +   O2(g)   à   NO2(g)   +   CO2(g)       (fast)

 

Rate of reaction is rate of slow step.   Rate = k [NO2]2

Expert Solution
Step 1

Given overall reaction is :

NO2 (g) + CO (g) ---------> NO (g) + CO2 (g) 

Mechanism is :

Step.1 :- 2NO2 (g) ----> 2NO (g) + O2 (g), slow 

Step.2 :- NO (g) + CO (g) + O2 (g) ---->NO2 (g)+ CO2 (g), fast 

What is the rate law of the reaction = ? 

 

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