what is the unit of the medium resistance and the specific cake resistance Data:Ws = 393g = 0.393 kg%3DP1 = 0.3 kg/cm²Po = 0.1 kg/cm²V1 = 10 LArea of filtrate tank (A) = 0.0398 m2%3DViscosity of the filtrate (u) = 9.03 ×10-5 N-sec/m2Density of white ceramic (p,) = 1600 kg/m3Vol = A xh= 0.0398 x 0.04 = 1.592 x 10-3 m³ДР — Р — Р.= 0.3 – 0.1 = 0.2 kg/cm2 = 2000kg/m²1804500%3DV/A0.04slope = m = 98193intercept = c = 649.78 To find the specific cake resistance (a):uxaxWsslopeΔΡΧ2χρs9.03 х10-5хах0.393= 981932000x2x160098193 x 2000x2x1600a =1.77 x 10169.03 x10-5 x 0.393To find the medium resistance (Lm):μχα= interceptAPx Lm9.03 x10-3x1.77×1016= 649.782000x Lm9.03 x10-5x1.77x1016Lm= 1.22 x 1062000x649.78

Given Resistance To find Unit of Cake resistance Unit of Medium resistance

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Engineering

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what is the unit of the medium resistance and the specific cake resistance

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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