What is the value of grade? grade = Math.abs(-5) * Math.min(-2, -6) а. -30 O b. -10 С. 30 O d. 10
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- What will the following Code segment print on the screen? int P = 30; int Q = 20; System.out.println("Your Total purchase is \n" + (Q*P) +" Dollars");issignment Portion - hand in your wo nce completed "4.2 (Geometry: gneat circle distance) The great circle distance is the distance between two points on the surface of a sphere. Let(x1,y1)and(x2,y2)be the geographical latitude and longitude of two points. The great circle distance between the two points can be computed using the following formula: \[ d=\operatorname{radius} \times \arccos \left(\sin \left(x_{1}\right) \times \sin \left(x_{2}\right)+\cos \left(x_{1}\right) \times \cos \left(x_{2}\right) \times \cos \left(y_{1}-y_{2}\right)\right) \] Write a program that prompts the user to enter the latitude and longitode of two points on the earth in degrees and displays its great circle distance. The average radius of the earth is6,371.01 km. Note you need to convert the degrees into radians using the Math, toRadi ans method since the Java trigonometric methods use radians. The latitude and longitude degrees in the formula are for north and west. Use negative to indicate south and…waht is value version
- In python. Write a program that calculates the BMI (Body Mass Index) of a person, which is used to determine if the ratio of weight and height is appropriate. BMI can be calculated using the following formula: index = weight / height ^ 2 Where the weight must be given in kilograms and the height in meters. The following table shows how the different index ranges are classified: index range Description index <20 LOW WEIGHT 20 <= index <25 NORMAL 25 <= index <30 OVERWEIGHT 30 <= index <40 OBESITY index >= 40 MORBID OBESITYint FindSmallestVal() { int num = 0, min = 0; // reads num until the num > 0 while (num <= 0) { cin >> num; // finds the min value in the min,num min = num < min ? num : min; } // returns min return min; }What is the opposite of greater than?
- # Write python codes here.print("Total E-Customer:", ECustomer.count)c1 = ECustomer("James")c1.setProductDetails("TV",35000,"Air Cooler", 9000)c2 = ECustomer("Mike")c2.setProductDetails("Mobile",20000,"Headphone",1200,"Fridge", 45000)c3 = ECustomer("Sarah")c3.setProductDetails("Headphone", 1200)print("=========================")c1.printDetail()print("=========================")c2.printDetail()print("=========================")c3.printDetail()print("=========================")print("Total E-Customer:", ECustomer.count)Output:Total E-Customer: 0=========================Name: JamesProducts: TV, Air CoolerTotal cost: 44000=========================Name: MikeProducts: Mobile, Headphone, FridgeTotal cost: 66200=========================Name: SarahProducts: HeadphoneTotal cost: 1200=========================Total E-Customer: 3Double any element's value that is less than minValue. Ex: If minValue = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}. #include <iostream>using namespace std; int main() {const int NUM_POINTS = 4;int dataPoints[NUM_POINTS];int minValue;int i; cin >> minValue; for (i = 0; i < NUM_POINTS; ++i) {cin >> dataPoints[i];} /* Your solution goes here */ for (i = 0; i < NUM_POINTS; ++i) {cout << dataPoints[i] << " " ;}cout << endl; return 0;} Please help me with this problem using c++.This code when ran asks for job code and then hours worked, but when I put in 20 or 40 hours I get an error... indexerror: Tuple index out of range Its supposed to be for up to 40 hours, no more then that.. how do I fix the tuple range? # Name: Erica Strong # Prog Purpose: This program computes employee weekly pay # Category codes: # C Cashier: $16.50 # S Stocker: $15.75 # J Janitor: $15.75 # M Maintenance: $19.50 import datetime # define pay rates & deduction rates PAY_RATES = (16.50, 15.75, 15.75, 19.50) DEDUCTION_RATES = (0.12, 0.03, 0.062, 0.0145) # define global variables inout = 'C' # C means Cashier, S means Stocker, J means Janitor, M means Maintenance hoursworked= 0 payrates = 0 deductionrates = 0 grosspay = 0 netpay = 0 ############ Define program functions ############ def main(): another_employee = True while another_employee: hours_worked, job_code = get_user_data() gross_pay = perform_calculations(hours_worked, job_code) total_deductions, deductions =…
- Question: Party budget planning - complex Prompt the user to enter their current budget and the number of people who need to share a meal. You are ordering food from a restaurant that has two menu items: Tacos $4 Empanadas $3 Calculate and print out all the options of meals where the budget is used entirely(where possible) and each person has an equal number of items to eat. They may eat different things, but everyone gets the same number of food items, e.g. 2 tacos or 1 empanada and 1 taco or 2 empanadas. Hints: Here are some things that might help you in your solution. If total items purchased does not equally divide by the number of diners, then abandon that combination. It may help to calculate the max number of empanadas that the budget can buy and also the max number of tacos that the budget could buy. These can be thought of as upper bounds in your loops. In your solution, keep track of items per person Also, keep track of total number of viable solutions, as that might…Question: Party budget planning - complex Prompt the user to enter their current budget and the number of people who need to share a meal. You are ordering food from a restaurant that has two menu items: Tacos $4 Empanadas $3 Calculate and print out all the options of meals where the budget is used entirely(where possible) and each person has an equal number of items to eat. They may eat different things, but everyone gets the same number of food items, e.g. 2 tacos or 1 empanada and 1 taco or 2 empanadas. Hints: Here are some things that might help you in your solution. If total items purchased does not equally divide by the number of diners, then abandon that combination. It may help to calculate the max number of empanadas that the budget can buy and also the max number of tacos that the budget could buy. These can be thought of as upper bounds in your loops. In your solution, keep track of items per person Also, keep track of total number of viable solutions, as that might…for (int value=3; pow (2, value) <=100; value++) cout << pow (2, value) << ": ";
