Given the following...int j;int sum;double sale[10][7];Which of the following correctly finds the sum of the elements of the fifth row of sale?03;0; j < 7; j++)sum + sale[5]a. sum =%3Dfor (j%3Dsum[j];b. sum = 0;%3D0; j < 7; j++)sum + sale[4]for (jsum[j];= 0;0; j< 10; j++)sum + sale[5]C. sumfor (jsum

b. sum = 0; for(j = 0; j < 7; j++) sum = sum + sale[4][j]; will find the sum of…

Given the following... int j; int sum; double sale[10][7]; Which of the following correctly finds the sum of the elements of the fifth row of sale? a. sum = 0; for (j = 0; j < 7; j++) sum = sum + sale[5] [j]; b. sum = 0; for(j = 0; j < 7; j++) sum = [j]; + sale[4] sum

Given the following... int j; int sum; double sale[10][7]; Which of the following correctly finds the sum of the elements of the fifth row of sale? a. sum = 0; for (j = 0; j < 7; j++) sum = sum + sale[5] [j]; b. sum = 0; for(j = 0; j < 7; j++) sum = [j]; + sale[4] sum

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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def find_root4(x, epsilon): ''' IN PYTHON Assume: x, epsilon are floating point numbers and epsilon > 0 Use bisection search to find the following root of x such that If x >=0, return y such that x - epsilon <= y ** 2 <= x + epsilon Else, return y such that x - epsilon <= y ** 7 <= x + epsilon Note: You must use bisection search to implement the function. ''' pass
Can you answer it based on the code below: #include #define MAX_EMP 5 struct Employee { int id; int age; float salary; }; int count = 0; struct Employee emp[MAX_EMP]; void display() { printf("\n---=== EMPLOYEE DATA ===---\n"); printf("EMP ID\tEMP AGE\tEMP SALARY\n"); printf("======\t=======\t==========\n"); for(int i = 0; i < count; i++) { printf("%d\t%d\t%.2f\n", emp[i].id, emp[i].age, emp[i].salary); } } void add() { if(count == MAX_EMP) { printf("\nERROR!!! Maximum Number of Employees Reached\n"); return; } printf("\nAdding Employee ===============\n"); printf("Enter Employee ID: "); scanf("%d", &emp[count].id); printf("Enter Employee Age: "); scanf("%d", &emp[count].age); printf("Enter Employee Salary: "); scanf("%f", &emp[count].salary); count++; } void update() { int id, found = 0; float newSalary; printf("\nUpdate Employee Salary…
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Can you answer it according to the code below #include #define MAX_EMP 5 struct Employee { int id; int age; float salary; }; int count = 0; struct Employee emp[MAX_EMP]; void display() { printf("\n---=== EMPLOYEE DATA ===---\n"); printf("EMP ID\tEMP AGE\tEMP SALARY\n"); printf("======\t=======\t==========\n"); for(int i = 0; i < count; i++) { printf("%d\t%d\t%.2f\n", emp[i].id, emp[i].age, emp[i].salary); } } void add() { if(count == MAX_EMP) { printf("\nERROR!!! Maximum Number of Employees Reached\n"); return; } printf("\nAdding Employee ===============\n"); printf("Enter Employee ID: "); scanf("%d", &emp[count].id); printf("Enter Employee Age: "); scanf("%d", &emp[count].age); printf("Enter Employee Salary: "); scanf("%f", &emp[count].salary); count++; } void update() { int id, found = 0; float newSalary; printf("\nUpdate Employee Salary…
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In Javascript, write code that prints the FIRST NAMES ONLY of people who have BOTH above average English grades AND below average age. Special conditions: Cannot use any array type built-in functions except filter(), map(), and reduce().
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Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for the rugged hero to tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The number of ways that a positive integer n can be represented as a sum of consecutive integers is called its politeness, and can also be computed by tallying up the number of odd divisors of that number. However, note that the linked Wikipedia de0inition…
Debug the following program and answer the following questions. #include <stdio.h> typedef struct node { int value; struct node *next; } node; int ll_has_cycle(node *first) { node * head = first; while (head->next) { head = head->next; if (head == first) return 1; } return 0; } void test_ll_has_cycle(void) { int i,j; node nodes[5]; for(i=0; i < sizeof(nodes)/sizeof(node); i++) { nodes[i].next = NULL; nodes[i].value = i; } nodes[0].next = &nodes[1]; nodes[1].next = &nodes[2]; nodes[2].next = &nodes[1]; printf("Checking first list for cycles. There should be a cycle, ll_has_cycle says it has %s cycle\n", ll_has_cycle(&nodes[1])?"a":"no"); printf("Checking length-zero list for cycles. There should be none, ll_has_cycle says it has %s cycle\n",…