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- 2.) A 0.2185g sample of NaCl was assayed using Volhard Method with 50mL 0f 0.0998N AgNO3 and 11.9mL of 0.1350N NH4SCN. Calculate the % NaCl in the sample.A sample is analyzed for chloride by the Volhard method. From the following data, calculate the percentage of chloride present:Weight of sample = 6.0000 g dissolved and diluted to 200 mLAliquot used = 25.00 mL AgNO3 added = 40.00ml of 0.1234MKSCN for back titration = 13.20ml of 0.0930MKnowing that Ksp of PbI2 = 10-⁷ find out if precipitate will form when mixing 100ml of 0.01 N Pb solution (NO3) 2 and 200ml of 0.01 M NaI solution
- What is the component concentration ratio, [Pr⁻]/[HPr], of abuffer that has a pH of 5.44 (Kₐ of HPr =1.3X10⁻⁵)?When standardizing two liters of a potassium permanganate solution with a primary standard solution of sodium oxalate, approximately 0.0100 M, it was planned to use between 30.00 mL and 45.00 mL of the titrated reagent. In which mass range (in grams) the primary standard should be weighed? Data: MM KMnO4 = 158.00 g/mol; MM Na2C2O4 = 134.00 g/mol 2CO2 + 2e- ↔ C2O4 2- Eo = -0,432 V MnO4 - + 8 H+ + 5e- ↔ Mn2+ + 4 H2O Eo = 1,52 VWhat is the cobalt(II) ion concentration in a solution prepared by mixing 357 mL357 mL of 0.396 M0.396 M cobalt(II) nitrate with 475 mL475 mL of 0.399 M0.399 M sodium hydroxide? The ?spKsp of cobalt(II) hydroxide is 5.92×10−155.92×10−15 .
- Standardization of EDTA was done using MgSO4 standard wherein a 50-mL aliquot of solution obtained from 0.480 g MgSO4 in 500 mL needed 39.4 mL of the EDTA solution to reach the endpoint. Determine how many milligrams of CaCO3 will react per mL of this EDTA solution.a) What mass of Fe(NH4)2(SO4)2•2H2O(s) is required to prepare a 500 mL solution containing 100 ppm (m:v) in Fe? b) Using this stock solution, what aliquot must be used to prepare calibration solutions, 100 mL volume, of the following concentrations: 0.100 ppm, 0.500 ppm, 2.00 ppm, 4.00 ppm, and 7.00 ppm.You are to make 300mL of 20mM EDTA buffer (C10H16N2O8) solution from powder. How much EDTA powder must be dissolved in water? [Atomic Weight: C = 12.011; H = 1.0079; O = 15.999; N = 14.0067]
- A commercial vinegar was analyzed by titration to determine the percent acetic acid. Briefly, 10.00 mL of vinegar sample was diluted to 100. mL solution in volumetric flask. A 25.00 mL aliquot from the diluted vinegar required 25.55 mL of 0.1005 M NaOH to reach the phenolphthalein endpoint. Which is the correct equation between the analyte and titrant reaction? CH3COOH + NaOH → NaCH3COO + H2O 2CH3COOH + NaOH → NaCH3COO + H2O C20H14O4 + NaOH → NaC20H14O4 + H2O CH3COOH + 2NaOH → NaCH3COO + H2OThe thiourea (NH2)2CS in a 1.600 g sample of an unknown organic material was extracted into a dilute acid solution and was titrated with 42.50 mL of 0.0010 M Hg2+. Equation: 4 (NH2)2CS + Hg2+ → [(NH2)2CS]4Hg2+ Find the percentage thiourea present in the sample.A 0.1214-g sample of impure Na2CO3 was analyzed by the Volhard method. After adding 50.00 mL of 0.07011 M AgNO3, the sample was back titrated with 0.06021 M KSCN, requiring 27.15 mL to reach the end point. State the net ionic equation.