What volume of 0.50 M H,SO, must be added to 65mL of 0.20 M H2SO, to give a final solution of 0.35 M? Assume volumes are additive.

Q: 4. What volume of 0.305 M AgNO3 is required to react exactly with 155.0 mL of 0.274 M NazS04…

A: Since you have posted multiple questions, we are entitled to answer the first only. 4) Given:…

Q: What the concentration (M) of NaCl solution prepared by dissolving 7.2 g of in sufficient water to…

A: We can determine the concentration in terms of molarity. Molarity is defined as the number of moles…

Q: Enter your answer in the provided box. What volume of 0.22 M H,SO, can be prepared by diluting 129…

A: We have to calculate the volume of 0.22 M of sulphuric acid that can be prepared from dilution of…

Q: Given the mole ratio of HCl to NaOH is 1:1 in the balanced acid base reaction A 15.52mL sample of…

A: HCl   +   NaOH   →   NaCl   +  H2OMolarity of NaOH = 0.976 MVolume of NaOH = 32.08 mL = 0.03208 L

Q: What mass of Naz CrO4 is required to precipitate all of the silver ions from 60.0 mL of a 0.600 M…

A: The balanced chemical reaction can be written as, Na2CrO4  + 2AgNO3 →Ag2CrO4  + 2NaNO3  The given…

Q: 780 mL of 0.0160 M AgNO, from the solid reagent. mL. Dissolve g AgNO, in enough water to give a…

A: a.) To calculate the grams of AgNO3 needed ,we would use Molarity formula .    (Note : Please upload…

Q: A solution contains an unknown mass of dissolved bariumions. When sodium sulfate is added to the…

A: The mass of barium was in the original solution has to be given,

Q: How many grams of PbBr2 will precipitate when excess BaBr2  solution is added to 78.0 ml of 0.524 M…

A: Recall the reaction that will occur here PbNO32 + BaBr2 →PbBr2 + BaNO32 Given that 78.0 ml of 0.524…

Q: How many mL of a 0.185 M (aq) solution of Ni(CH3COO)2, must be taken to get 4.68g of the salt?

A: For the determination of substance’s moles (dissolved solute) that are available in 1 L solution,…

Q: Given the mole ratio of HCl to NaOH is 1:1 in the balanced acid base reaction A 15.52mL sample of…

A:

Q: What is the final concentration of Na+ in a solution created by mixing 200 mL of 0.40M NaCl with 800…

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Q: Solid ammonium sulfite is slowly added to 150 mL of a 0.140 M silver fluoride solution until the…

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Q: If 41.5 g of CH₃OH (MM = 32.04 g/mol) are dissolved in 500.0 mL of solution, what is the…

A: The molarity of the solution is defined by the mole of solute present in one liter of solution. The…

Q: What information can we get from the molarity of a solution that we cannot know from its percentage…

A: Introduction: There are various ways to express the concentration of solutions, ions etc. in…

Q: If 16.95 mL of a solution of NaOH is required to titrate a 0.3556 g sample of KHP dissolved in 25.00…

A: Molarity is the number of moles of solute dissolved per litre of solution.

Q: What volume of 0.171 M KOH,0.171 M KOH, ?,V, can be neutralized with 58.5 mL58.5 mL of 1.21 M HNO3?…

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Q: Titration of a 10.0 mL sample of acid rain required 2.1 mL of 0.0824 M KOH to reach the end point.…

A: Given: Volume of sample is 10 mL. Volume of base is 2.1 mL. Molarity of base solution is 0.0824 M.…

Q: A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO,),(aq), until no further…

A: Stoichiometric relation help in finding the relationship between the quantity of reactant and…

Q: If 20. g of AgNO, is available, what volume of 0.25 M AGNO, solution can be prepared? 1S Volume %3D…

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Q: 200ml or o.Smol/L of barum nitrante solution is poured intoa heaker containing 100 of 0.Smo/L. of…

A: 9.Given that, Volume of 0.5mol/L Ba(NO3)2 solution= 200 mL = 0.2 L Volume of 0.5mol/L Na2SO4…

Q: What volume (mL) is required from a stock solution of 1.98m KNO3 to prepare a 750ml solution of 1.00…

A: We can solve the problem from the following formula : V 1 S 1 = V 2 S 2    Where : V1 = initial…

Q: A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO,),(aq), until no further…

A: Given mass of lead (II) chloride =12.18 g Molar mass of lead (II) chloride = 278.1 g/mol Number of…

Q: What volume in milliliters of 0.0170 M Ca(OH), is required to neutralize 70.0 mL of 0.0300 M HBr?

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Q: A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO,),(aq), until no further…

A:

Q: A solution of 100.0 mL of 0.200 M KOH is mixed with a solutionof 200.0 mL of 0.150 M NiSO4. (a)…

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Q: What volume of 0.165 M Na3PO4 solution is necessary to completely react with 88.6 mL of 0.106 M…

A: Given balanced chemical equation is 2Na3PO4 (aq) + 3CuCl2(aq) →Cu3(PO4)2(s) + 6 NaCl(aq)…

Q: How many milliliters of 9.81 M nitric acid solution should be used to prepare 2.00 L of 0.700 M…

A: Here we use dilution  law   M1V1 = M2V2

Q: Enter your answer in the provided box. What volume of 5.00 M H,SO, is needed to prepare 390.0 mL of…

A:

Q: A 500.0ml solution of concentration 2.00M is diluted to a volume of 1.00L.  What is the final…

A: The relation between initial and final molarity of the solution after dilution is given in equation…

Q: A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO,),(aq), until no further…

A: Balanced reaction of Pb(NO3)2 with NaCl Pb(NO3)2(aq) + 2NaCl(aq) ....> PbCl2(s) + 2NaNO3(aq) Mass…

Q: a. If 15.0 ml of H.SO.are required to neutralize 25.0 ml of 0.660 N KOH solutton, to what volume…

A:

Q: Calculate the mass, in grams, of sodium bicarbonate (NaHCO3) that is required to neutralize 126 mL…

A: Given: Sodium bicarbonate neutralizes HCl solution.

Q: What volume of your solution, (concentration of 0.184) is required to react completely with 55.0 mL…

A: This problem can be solved by using the molarity equation: M1V1 = M2V2 where M1 and V1 are the…

Q: What volume of 0.416 M mg(no3)2 should be added to 255ml of 0.102M KNO3 to produce a solution with a…

A: Given, Concentration of Mg(NO3)2 = 0.416M. Volume of KNO3 = 255mL. Concentration of KNO3 = 0.102M.…

Q: What volume in mL of 0.220 M HBr solution is required to produce 0.0210 moles of HBr?

A: Number of moles = Molarity (mol/L ) × Volume( L)

Q: A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO,),(aq), until no further…

A: The reaction of aqueous solutions of NaCl with PbNO32gives the precipitate PbCl2and aqueous solution…

Q: to

A:

Q: A solution of NaCI(aq) is added slowly to a solution of lead nitrate, Pb(NO,),(aq), until no further…

A: First we find the moles of PbCl2 , from the moles of PbCl2 and using the Balanced chemical equation…

Q: How many grams of Cu(OH)2 will precipitate when excess Ba(OH), solution is added to 63.0 mL of 0.506…

A: Molarity of CuI2 solution = 0.506 M Volume of CuI2 solution = 63.0 mL = 0.063 L  We need to find…

Q: What mass of Naz CrO4 is required to precipitate all of the silver ions from 20.0 mL of a 0.200 M…

A:

Q: What volume in milliliters of O.0190 M Sr(OH), is required to neutralize 65.0 mL of 0.0400 M HCI?

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Q: A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO,),(aq), until no further…

A:

Q: Calculate the concentration of all 1ons present in 0.472 g AlCl, in 250.0 mL of solution. MAI?+ MCl-

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Q: A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO,),(aq), until no further…

A: Explanation Molarity (M): The number of moles of solute dissolved in one litre (L) of the solution…

Q: What mass of Na z CO3 is rquired to react completly with 21.6 ml of 0.120M HCI ?

A: The reaction between HCl and Na2CO3 is as follows: Na2CO3 + 2HCl →2 NaCl + H2CO3 The moles of HCl…

Q: What volume of 0.416M Mg(NO3)2 should be added to 255 mL of 0.102 M KNO3 to produce a solution with…

A:

Q: How many miiters of 0.127 M H;SO, are needed to neutralize 0.250 g of NaOH? Express the volume in…

A: Given : Concentration of H2SO4 = 0.127 M And mass of NaOH = 0.250 g The neutralisation reaction…

Q: What volume of 21.0 M HNO, must be diluted with distilled water to prepare 5.00L of 0.450 M HNO3?

A:

Q: What volume of 0.205 M K, PO, solution is necessary to completely react with 138 mL of 0.0104 M NiC,…

A: K3PO4  molarity = 0.205 M  Volume of K3PO4 = V litre  Number of moles = 0.205 V NiCl2  Molarity =…

Q: Titration of a 25.00 mL sample of acid rain required 13.23 mL of 0.009567 M KOH to reach the end…

A: