Asked Nov 25, 2019

What volume of carbon dioxide gas at 0.980 atm and 293 K could be made from reacting 10.0 grams of sodium carbonate with 100. mL of 6.0 M HCl? This is a limiting reactant problem.
Given: Na2CO3 (s) + 2 HCl (aq) -> 2 NaCl (aq) + H2O (g) + CO2 (g)


Expert Answer

Step 1

Solution stoichiometry is mainly based on the calculation of moles and volumes. These two values are used to calculate the molarity of solution. The relation between moles, volume and molarity is as given below;


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Moles of solute Molarity volume of solution in L Mass of solute ing Molar mass of solute (g/mol) Moles =

Step 2

Calculate moles of Na2CO3:

Molar mass of Na2CO3 = 106 g/mol

Mass of Na2CO3 = 10.0 g


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Mass in g Moles Molar mass (g/mol) 10.0 g Moles 0.094moles 106 g/mol

Step 3

Calculate moles of HCl:

Volume of HCl = 100 mL  =...


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Moles Molarity volume of solution in L Moles 6.0 M 0.1 L Moles 6.0M-0.1L = 0.6 moles


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