When 4.007 grams of a hydrocarbon, C,Hy, were burned in a combustion analysis apparatus, 12.14 grams of CO, and 6.212 grams of H20 were produced. In a separate experiment, the molar mass of the compound was found to be 58.12 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula = molecular formula =

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Chapter6: Chemical Calculations: Formula Masses, Moles, And Chemical Equations
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When 4.007 grams of a hydrocarbon, C,Hy, were burned in a combustion analysis apparatus, 12.14 grams of CO, and 6.212 grams
of H20 were produced.
In a separate experiment, the molar mass of the compound was found to be 58.12 g/mol. Determine the empirical formula and the
molecular formula of the hydrocarbon.
Enter the elements in the order presented in the question.
empirical formula =
molecular formula =
Transcribed Image Text:When 4.007 grams of a hydrocarbon, C,Hy, were burned in a combustion analysis apparatus, 12.14 grams of CO, and 6.212 grams of H20 were produced. In a separate experiment, the molar mass of the compound was found to be 58.12 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula = molecular formula =
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