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When 5.58 g of a solid mixture composed of NH4CI and CaCl2 was dissolved in 100.0 mL of water, the temperature of the water rose by 4.86°C. How many grams of each substance was in the mixture? Include the mass of salts in calculation of heat generated. g NH4CI = i g CaCl2 = i

When 5.58 g of a solid mixture composed of NH4CI and CaCl2 was dissolved in 100.0 mL of water, the temperature of the water rose by 4.86°C. How many grams of each substance was in the mixture? Include the mass of salts in calculation of heat generated. g NH4CI = i g CaCl2 = i

Human Physiology: From Cells to Systems (MindTap Course List)
Human Physiology: From Cells to Systems (MindTap Course List)
9th Edition
ISBN:9781285866932
Author:Lauralee Sherwood
Publisher:Lauralee Sherwood
Chapter3: The Plasma Membrane And Membrane Potential
Section: Chapter Questions
Problem 1SQE: Using the Nernst equation, calculate the equilibrium potential for Ca2 and for C1 from the following...
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When 5.58 g of a solid mixture composed of NH4CI and CaCl2 was dissolved in 100.0 mL of water, the temperature of the water rose by 4.86°C. How many grams of each substance was in the mixture? Include the mass of salts in calculation of heat generated. g NH4CI = i g CaCl2 = i
Transcribed Image Text:When 5.58 g of a solid mixture composed of NH4CI and CaCl2 was dissolved in 100.0 mL of water, the temperature of the water rose by 4.86°C. How many grams of each substance was in the mixture? Include the mass of salts in calculation of heat generated. g NH4CI = i g CaCl2 = i
The value of AH° for HBr(g) was first evaluated using the following standard enthalpy values obtained experimentally. Use these data to calculate the value of AHf° for HBr(g). Cl,(g)+2KB1(ag) – Br, (ag)+2KCI(ag) AH° =-96.2 kJ H,(g)+Cl, (g)- HCl(aq)+ KOH(aq) KC(aq)+H,O(!) 2HCI(g) AH° =-184 kJ AH° =-57.3 kJ HBr(aq)+ KOH(aq) KBr(aq)+ H,O(!) AH° =-57.3 kJ AH° =-77.0 kJ HC(g) Br,(g) HBr(g)- HCl(aq) disdlving in water Br, (aq) AH° =-4.2 kJ disolving in water HBr(aq) AH° =-79.9 kJ dissolving in water ΔΗΡ- i kJ
Transcribed Image Text:The value of AH° for HBr(g) was first evaluated using the following standard enthalpy values obtained experimentally. Use these data to calculate the value of AHf° for HBr(g). Cl,(g)+2KB1(ag) – Br, (ag)+2KCI(ag) AH° =-96.2 kJ H,(g)+Cl, (g)- HCl(aq)+ KOH(aq) KC(aq)+H,O(!) 2HCI(g) AH° =-184 kJ AH° =-57.3 kJ HBr(aq)+ KOH(aq) KBr(aq)+ H,O(!) AH° =-57.3 kJ AH° =-77.0 kJ HC(g) Br,(g) HBr(g)- HCl(aq) disdlving in water Br, (aq) AH° =-4.2 kJ disolving in water HBr(aq) AH° =-79.9 kJ dissolving in water ΔΗΡ- i kJ
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