(a) Calculate the value of Kc for the reaction:PCl5 (g) PCl3 (g) + Cl2 (g) ΔH = Positive Given that when 8.4 mol of PCl5 (g) is mixed with 1.8 mol of PCl3 (g) and allowed to come to equilibrium in a 10 dm3container the amount of PCl5 (g) at equilibrium is 7.2 mol. Kc = (b) Explain the effect of the following changes below on the value of Kc: Increasing temperature Lowering the concentration of chlorine (Cl2) Addition of a catalyst

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Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 15P

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(a) Calculate the value of Kc for the reaction:

PCl_{5 (g)} PCl₃ _(g) + Cl₂ _(g) ΔH = Positive

Given that when 8.4 mol of PCl₅ _(g) is mixed with 1.8 mol of PCl₃ _(g) and allowed to come to equilibrium in a 10 dm³container the amount of PCl₅ _(g) at equilibrium is 7.2 mol.

Kc =

(b) Explain the effect of the following changes below on the value of Kc:

Increasing temperature

Lowering the concentration of chlorine (Cl₂)

Addition of a catalyst

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i believe your ans for Kc is incorrect

with Kc = 0.05

Examples of cal. Kc.
Calculate the value of Kc for the reacher.
PCLSS
= P C3(g) + Cl₂(g).
Given that when 8.4 mol of PCs (s) is mixed
with 1-8 mor of PCL3(g) & allowed to come
to equilibrium in a 10dm³ container the
amount of PC`s(s) at equilibrum is 7.2 mol.
PCL5
- PCI 3
ndes initially 8.4
84-102
7-2
nores@eqmail.
Full conc in
mol/dm³
7-2
10.
13.29
+ Cl₂.
1.8.
(²+1.8) 1.2.
3.0/10
1-2
10.
= 0-72
0.30.
012.
kc = [PC13 ] [C1₂] = [03][012]=K=00
[PCL5]
En = takes in
Ex = gives
+
out.
ma

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