When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4385 rpm to zero in 3.25 s .What is the angular acceleration of the blade?What is the distance traveled by a point on the rim of the blade during the deceleration?What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration?

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Asked Oct 18, 2019
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When a carpenter shuts off his circular saw, the 10.0-inch-diameter blade slows from 4385 rpm to zero in 3.25 s .

What is the angular acceleration of the blade?

What is the distance traveled by a point on the rim of the blade during the deceleration?

What is the magnitude of the net displacement of a point on the rim of the blade during the deceleration?

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Expert Answer

Step 1

Given:

Diameter of the blade = 10 inch

Radius of the blade = 5 inch

Angular velocity = 4385 rpm

Time taken = 3.25 s

Step 2

Calculating the angular accel...

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Initial angular veloty. w=4585 pm 4385 x 2 OR wi = rad/s 6 0 459 rad/s Final angular velouty =0 tme taken, t- °3.255 Angulas acceteration o-4 59 OR a= rad/s 3-25 a = -141-23 Tad/s2 soiny ad 141-33 rad/s doun Negative sign means blade is

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