When ammonia (NH3) reacts with fluorine (F2), the products are dinitrogen tetrafluoride and hydrogen fluoride. 2NH3 +5F2 = N2F4+6HF 1. How many moles of NH3 are needed to produce 4.30 mol of N2F4? 2. How many moles of F2 are needed to produce 4.30 mol of N2F4? 3. How many grams of F2 are required to react with 25.1g of NH3? 4. How many grams of HF can be produced when 4.30g of NH3 reacts?

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