Question
Asked Sep 30, 2019
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When an identical 4.008 g of sulfur is burned completely in a restricted amount of air, it again combines with oxygen to form a single gaseous product, but this time the total mass of the product is 8.008 g. What is the mass perfect of sulfur and oxyegn in the gaseous product?

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Expert Answer

Step 1

Given,

Sulfur is burned completely in a restricted amount of air, it again combines with oxygen to form a single gaseous product. The reaction can be written as:

S + O2 → SO2

Mass of sulfur (S) = 4.008 g

Mass of product (SO2) = 8.008 g

Step 2

Law of conservation of mass states that the mass of reactant is equal to the mass of products.

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Mass of S Mass of O2 Mass of SO2 Mass of O2 Mass of SO2 - Mass of S Mass of O2 8.008 g - 4.008 g = 4.000 g

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Step 3

The mass percent of sulfur and oxygen in the ...

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Mass of S Mass of S Mass of product * 100 % Mass % ofs 4.008 g 100 % = 50.05 % 8.008 g Mass of O2 Mass % of O2Mass of product * 100 % Mass % of O= 4.000 g 100 %= 49.95 % 8.008 g

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