When heated, solid potas 0₂ (8) unbalanced equation: KCIO3(s) → KCI) + f 20.8 g of potassium chlorate decomposes, how many liters of oxygen gas will form at STP?

Chemistry: Matter and Change
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Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
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Chapter13: Gases
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Problem 89A
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9. When heated, solid potassium chlorate decomposes to form solid potassium chloride and oxygen gas according to this
unbalanced equation:
KCIO3(s) →
KCl (s) +
O2 (g)
If 20.8 g of potassium chlorate decomposes, how many liters of oxygen gas will form at STP?
Transcribed Image Text:9. When heated, solid potassium chlorate decomposes to form solid potassium chloride and oxygen gas according to this unbalanced equation: KCIO3(s) → KCl (s) + O2 (g) If 20.8 g of potassium chlorate decomposes, how many liters of oxygen gas will form at STP?
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