When sodium and oxygen react, one of the products obtained is sodium peroxide, Na2O2. The anion in this compound is the peroxide ion, O22- . Write the electron configuration for this ion in molecular orbital terms, and then compare it with the electron configuration of the O2 molecule with respect to the following criteria: (i) magnetic character (ii) net number of sigma and pi bonds (iii) bond order (iv) oxygen–oxygen bond length
When sodium and oxygen react, one of the products obtained is sodium peroxide, Na2O2. The anion in this compound is the peroxide ion, O22- . Write the electron configuration for this ion in molecular orbital terms, and then compare it with the electron configuration of the O2 molecule with respect to the following criteria: (i) magnetic character (ii) net number of sigma and pi bonds (iii) bond order (iv) oxygen–oxygen bond length
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter9: Bonding And Molecular Structure: Orbital Hybridization And Molecular Orbitals
Section9.2: Molecular Orbital Theory
Problem 9.6CYU: The cations O2+ and N2+ are formed when molecules of O2 and N2 are subjected to intense, high-energy...
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When sodium and oxygen react, one of the products obtained is sodium peroxide, Na2O2. The anion in this compound is the peroxide ion, O22- . Write the electron configuration for this ion in molecular orbital terms, and then compare it with the electron configuration of the O2 molecule with respect to the following criteria:
(i) magnetic character
(ii) net number of sigma and pi bonds
(iii) bond order
(iv) oxygen–oxygen bond length
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