When the temperature-time data graph was reviewed, it was found that an error had been made in determining ΔT. Instead of 4.76 °C, ΔT was actually 4.70 °C. Based on this change only, calculate the correct ΔH neutralization for the reaction of NH3, and acetic acid.

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When the temperature-time data graph was reviewed, it was found that an error had been made in determining ΔT. Instead of 4.76 °C, ΔT was actually 4.70 °C. Based on this change only, calculate the correct ΔH neutralization for the reaction of NH3, and acetic acid.
1988 Cengage Learning
oriw olemtiolo odt oi quo msolone or zol 1od eesig6gnuliedue lo dia obieno.C
alubom ei ni bodoesb insminoo srli aob
2. When a neutralization reaction was carried out using 100.0 mL of 0.7890M NH3 water and 100.0 mL of
0.7940M acetic acid, AT was found to be 4.76 °C. The specific heat of the reaction mixture was 4.104 J
-1
K-1
and its density was 1.03 g mL-1. The calorimeter constant was 3.36 J K-1.
(1) Calculate AHmeutzn for the reaction of NH3 and acetic acid.
heat absorbed by reaction= (volume)(density) (AT) (specific hcat)
(200 mL)(1.03)(4.76) (4.104)
= 4,0 24. 22
heat absorbed by calorimeter =falorimet er constant)(AT)
= 3.36 (4.76) =15. 99
total heat =(heat absorbed by mixture) +heat absexbed bu calorimeter)oW (S)
= 4. 04 E 3 4,044 KJ
3o bseten
AH 404.
.0774
61U2 KJ/mol
limiting Moks of NHs=0.789-.130.0789 mol
agent
moles of CHs COOH=.794-.=,0794 mol
answer
(2) At the end of the experiment, it was discovered that the thermometer had not been calibrated.
When it was calibrated, it was found that the thermometer read 0.50 °C low. What effect would
this thermometer reading have on the reported AHneutzn calculated in (2) above?
Transcribed Image Text:1988 Cengage Learning oriw olemtiolo odt oi quo msolone or zol 1od eesig6gnuliedue lo dia obieno.C alubom ei ni bodoesb insminoo srli aob 2. When a neutralization reaction was carried out using 100.0 mL of 0.7890M NH3 water and 100.0 mL of 0.7940M acetic acid, AT was found to be 4.76 °C. The specific heat of the reaction mixture was 4.104 J -1 K-1 and its density was 1.03 g mL-1. The calorimeter constant was 3.36 J K-1. (1) Calculate AHmeutzn for the reaction of NH3 and acetic acid. heat absorbed by reaction= (volume)(density) (AT) (specific hcat) (200 mL)(1.03)(4.76) (4.104) = 4,0 24. 22 heat absorbed by calorimeter =falorimet er constant)(AT) = 3.36 (4.76) =15. 99 total heat =(heat absorbed by mixture) +heat absexbed bu calorimeter)oW (S) = 4. 04 E 3 4,044 KJ 3o bseten AH 404. .0774 61U2 KJ/mol limiting Moks of NHs=0.789-.130.0789 mol agent moles of CHs COOH=.794-.=,0794 mol answer (2) At the end of the experiment, it was discovered that the thermometer had not been calibrated. When it was calibrated, it was found that the thermometer read 0.50 °C low. What effect would this thermometer reading have on the reported AHneutzn calculated in (2) above?
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