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When treated with acid, lead(IV) oxide is reduced to a lead(II) salt, with the liberation of oxygen: 2 PbO2(s) + 4 HNO3(aq)→ 2 Pb(NO3)2(aq) + 2 H,O(€) + O2(g) What volume of a 7.91 M solution of nitric acid is just sufficient to react with 15.9 g of lead(IV) oxide, according to this equation?

When treated with acid, lead(IV) oxide is reduced to a lead(II) salt, with the liberation of oxygen: 2 PbO2(s) + 4 HNO3(aq)→ 2 Pb(NO3)2(aq) + 2 H,O(€) + O2(g) What volume of a 7.91 M solution of nitric acid is just sufficient to react with 15.9 g of lead(IV) oxide, according to this equation?

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter11: Solutions
Section: Chapter Questions
Problem 15P
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When treated with acid, lead(IV) oxide is reduced to a lead(II) salt, with the liberation of oxygen: 2 PbO2(s) + 4 HNO3(aq)→ 2 Pb(NO3)2(aq) + 2 H,O(€) + O2(g) What volume of a 7.91 M solution of nitric acid is just sufficient to react with 15.9 g of lead(IV) oxide, according to this equation?
Transcribed Image Text:When treated with acid, lead(IV) oxide is reduced to a lead(II) salt, with the liberation of oxygen: 2 PbO2(s) + 4 HNO3(aq)→ 2 Pb(NO3)2(aq) + 2 H,O(€) + O2(g) What volume of a 7.91 M solution of nitric acid is just sufficient to react with 15.9 g of lead(IV) oxide, according to this equation?
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