When working on a normal distribution other than the standard normal distribution you need to either first convert to the z-scores and then find probabilities using the standard normal distribution (N(0,1)) OR when using technology you can input the mean and standard deviation. P (a < X < b) = normalcdf(a,b,μ, o)=normalcdf(staring data value, ending data value, mean, standard deviation) to find the probability given the interval of data values. This is equal to P(

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When working on a normal distribution other than the standard normal distribution you
need to either first convert to the z-scores and then find probabilities using the standard
normal distribution (N(0,1)) OR when using technology you can input the mean and
standard deviation.
P (a < X < b) = normalcdf(a,b,, σ)=normalcdf(staring data value, ending data value, mean,
standard deviation) to find the probability given the interval of data values.
)-normalcdf(smaller z-score, larger z-
This is equal to P(<Z<b=) = normalcdf(
score)
a f
For finding the data value given the area you can use invNorm. Again you either need to
convert the z-score back to the data value OR tell the calculator the mean and standard
deviaiton.
invNorm(area to the left, mean, standard deviation) = data value =X
invNorm(area to the left) = Z = Z-score. Then X = μ + Z.o
IQ's are normally distributed with a mean of 100 and a standard deviation of 15. What is
the probability that someone randomly picked from the population has an IQ of 90 or
lower?
Transcribed Image Text:When working on a normal distribution other than the standard normal distribution you need to either first convert to the z-scores and then find probabilities using the standard normal distribution (N(0,1)) OR when using technology you can input the mean and standard deviation. P (a < X < b) = normalcdf(a,b,, σ)=normalcdf(staring data value, ending data value, mean, standard deviation) to find the probability given the interval of data values. )-normalcdf(smaller z-score, larger z- This is equal to P(<Z<b=) = normalcdf( score) a f For finding the data value given the area you can use invNorm. Again you either need to convert the z-score back to the data value OR tell the calculator the mean and standard deviaiton. invNorm(area to the left, mean, standard deviation) = data value =X invNorm(area to the left) = Z = Z-score. Then X = μ + Z.o IQ's are normally distributed with a mean of 100 and a standard deviation of 15. What is the probability that someone randomly picked from the population has an IQ of 90 or lower?
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