When you are presented with additional details, it can sometimes be a little more difficult to determine which information is necessary and how molarity should be applied. Using both a solution map and dimensional analysis can help clarify which information and conversion factors are necessary to determine the desired value. The following dimensional analysis setup could be used to determine the theoretical mass of AlBr3 (s) (molecular mass = 266.69 g/mol ) produced based on reacting 86.9 g of a 0.048 mol/L solution of Br2 (1) (density = 1036 g/L ) with excess Al(s) as described in the following equation: 3Br2 (1) + 2Al(s) → 2AIBr3 (s) Complete the dimensional analysis for calculating the mass of the product by placing the values of each conversion factor according to whether they should appear in the numerator or denominator when calculating the mass of AlBr3 (s) produced from a sample of Br2 (1). Drag the appropriate values to their respective targets. • View Available Hint(s) Reset Help 0.048 mol Br2(1) 1L solution 266.69 g AlBr3(s) 1 mol AlBr3(s) 1L solution 1036 g Br2(1) 86.9 g Br2(1) 3 mol Br2(1) 2 mol AlBr3(s) Group 1 Group 2 Group 4 Group 3 Group 1 Group 1 Group 2 Group 4 Group 3
When you are presented with additional details, it can sometimes be a little more difficult to determine which information is necessary and how molarity should be applied. Using both a solution map and dimensional analysis can help clarify which information and conversion factors are necessary to determine the desired value. The following dimensional analysis setup could be used to determine the theoretical mass of AlBr3 (s) (molecular mass = 266.69 g/mol ) produced based on reacting 86.9 g of a 0.048 mol/L solution of Br2 (1) (density = 1036 g/L ) with excess Al(s) as described in the following equation: 3Br2 (1) + 2Al(s) → 2AIBr3 (s) Complete the dimensional analysis for calculating the mass of the product by placing the values of each conversion factor according to whether they should appear in the numerator or denominator when calculating the mass of AlBr3 (s) produced from a sample of Br2 (1). Drag the appropriate values to their respective targets. • View Available Hint(s) Reset Help 0.048 mol Br2(1) 1L solution 266.69 g AlBr3(s) 1 mol AlBr3(s) 1L solution 1036 g Br2(1) 86.9 g Br2(1) 3 mol Br2(1) 2 mol AlBr3(s) Group 1 Group 2 Group 4 Group 3 Group 1 Group 1 Group 2 Group 4 Group 3
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter6: Types Of Chemical Reactions And Solution Stoichiometry
Section: Chapter Questions
Problem 126CP
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Transcribed Image Text:When you are presented with additional details, it can sometimes be a little more difficult to determine which information is necessary and how molarity should be applied. Using both a solution
map and dimensional analysis can help clarify which information and conversion factors are necessary to determine the desired value.
The following dimensional analysis setup could be used to determine the theoretical mass of AlBr3 (s) (molecular mass = 266.69 g/mol ) produced based on reacting 86.9 g of a 0.048
mol/L solution of Br2 (1) (density = 1036 g/L ) with excess Al(s) as described in the following equation:
3B12 (1) + 2A1(s) → 2AIBr3 (s)
Complete the dimensional analysis for calculating the mass of the product by placing the values of each conversion factor according to whether they should appear in the numerator or
denominator when calculating the mass of AlBr3 (s) produced from a sample of Br2 (1).
Drag the appropriate values to their respective targets.
• View Available Hint(s)
Reset
Help
0.048 mol Br2(1)
1 L solution
266.69 g AlBr3 (s)
1 mol AlBr3(s)
1 L solution
1036 g Br2(1)
86.9 g Br2(1)
3 mol Br2(1)
2 mol AlBr3(s)
Group 1
Group 2
Group 4
Group 3
Group 1
Group 1
Group 2
Group 4
Group 3
P Pearson
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