When you solve for acid molarity in a titration lab that gives you the base molarity, initial/final burette reading, and volume of the acid used in reaction. Is the formula to find the acid molarity M1 x V1 = M2 x V2...? Isnt that just the dilution formula?
When you solve for acid molarity in a titration lab that gives you the base molarity, initial/final burette reading, and volume of the acid used in reaction. Is the formula to find the acid molarity M1 x V1 = M2 x V2...? Isnt that just the dilution formula?
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.123QP: A 0.608-g sample of fertilizer contained nitrogen as ammonium sulfate, (NH4)2SO4. It was analyzed...
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When you solve for acid molarity in a titration lab that gives you the base molarity, initial/final burette reading, and volume of the acid used in reaction. Is the formula to find the acid molarity M1 x V1 = M2 x V2...? Isnt that just the dilution formula?
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