Which change in the system will drive equilibrium to the left in the reaction below? N 20 5( g) = NO 2(g) + NO 3( 8) A. increase the volume B. increase the amount of N 20 5 C. increase the pressure D. decrease the amount of NO 3 An acidic solution at 25°C has O A. (H 30 *)> [OH] >1 × 10 -7 M. [H 30 *)> 1 x 10 -/ M > [OH "]. [H 30 *] < 1 × 10 -7 M > [OH ]. O D. (H 30 *) = [OH ]>1 × 10-7 M.
Which change in the system will drive equilibrium to the left in the reaction below? N 20 5( g) = NO 2(g) + NO 3( 8) A. increase the volume B. increase the amount of N 20 5 C. increase the pressure D. decrease the amount of NO 3 An acidic solution at 25°C has O A. (H 30 *)> [OH] >1 × 10 -7 M. [H 30 *)> 1 x 10 -/ M > [OH "]. [H 30 *] < 1 × 10 -7 M > [OH ]. O D. (H 30 *) = [OH ]>1 × 10-7 M.
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter17: Equilibrium
Section: Chapter Questions
Problem 30QAP: . Consider the reaction 2CO(g)+O2(g)2CO2(g)Suppose the system is already at equilibrium, and then an...
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For the first question the answer isn't increase the volume
Could you please help me with both
Transcribed Image Text:Which change in the system will drive equilibrium to the left in the reaction below?
N 20 5( g) = NO 2(g) + NO 3( 8)
A. increase the volume
B. increase the amount of N 20 5
C. increase the pressure
D. decrease the amount of NO 3
![An acidic solution at 25°C has
O A. (H 30 *)> [OH] >1 × 10 -7 M.
[H 30 *)> 1 x 10 -/ M > [OH "].
[H 30 *] < 1 × 10 -7 M > [OH ].
O D. (H 30 *) = [OH ]>1 × 10-7 M.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6f9ca2ce-c481-46d9-90b7-dd41b10c6161%2F867585f2-71bf-41f2-b396-d201ef73aaf6%2Fv5f8g6.png&w=3840&q=75)
Transcribed Image Text:An acidic solution at 25°C has
O A. (H 30 *)> [OH] >1 × 10 -7 M.
[H 30 *)> 1 x 10 -/ M > [OH "].
[H 30 *] < 1 × 10 -7 M > [OH ].
O D. (H 30 *) = [OH ]>1 × 10-7 M.
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