Which statements apply to an SN1 reaction? I. The reaction produces a racemic mixture even if the reactive center of the substrate is not chiral. II. The order of reactivity for the substrate is methyl > 1°> 2° > 3°. III. The alkyl halide is involved in the rate determining step. IV. There is a carbocation intermediate. Select one: O II, IV O II, II O I, II, IV O I, IV O All of them
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- Please state if the substrate below undergoes carbocation rearrangement in an SN1 mechanism Thank youWhy does the final product has the opposite configuration compared to the reactant? Shouldn’t it form OMs first, then OMs gets substituted by Cl- via Sn2 (the 1st inversion of configuration) then the Cl- gets substituted by OCH3- (the 2nd inversion of configuration? To my understanding 2 inversions = same configuration1. what is the Nature of the leaving group (LG)? 2. what is the relative size of activation energy (Ea) for each reaction? 3. what is the Hammond's postulate? 4. what are the Relative thermodynamic stability of the reactive intermediates? 5. what is Influence of the solvent (if given) on the reactions and intermediates?
- Chemistry Find the most efficient synthetic route for the followinf transformations.Why are SN1 reactions favored by polar protic solvents? Group of answer choices Polar protic solvents stabilize reaction intermediates Polar protic solvents cannot form hydrogen bonds. Polar protic solvents contribute leaving groups. Polar protic solvents contribute leaving groups.The use of curved arrows is a powerful tool that illustrates even complex reactions. a.Add curved arrows to show how carbocation A is converted to carbocation B. Label each new σ bond formed. Similar reactions have been used in elegant syntheses of steroids. b.Draw the product by following the curved arrows. This reaction is an example of a [3,3] sigmatropic rearrangement, as we will learn in Chapter 25.
- Draw the molecule: Under second-order conditions (strong base/nucleophile), SN2 and E2 reactions may occur simultaneously and compete with each other.Show what products might be expected from the reaction of 2-bromo-3-methylbutane (a moderately hindered 2∘∘ alkyl halide) with sodium ethoxide. Do not worry about sterechemistry inther SN2 product for this problem. Don't forget about stereochemistry.Q4 Which statement below about Sn1 reactions is incorrect? (A) SN1 reactions are stepwise and have intermediates. (B) The slow step in a SN1 reaction is formation of the carbocation intermediate. (C) SN1 reactions have first order kinetics which means only the alkyl halide is involved in the rate limiting step. (D) The products of a SN1 reaction will be a pair of enantiomers. (E) An aprotic solvent is best for Sn1 reactions as they tend to help stabilize carbocation intermediates.What substrate below is ideal for SN1 reaction?
- 1. Which of the following is the strongest nucleophile? Refer to the diagram below with an MeOH, MeSH, etc. 2. Which of the following is true about the stereochemistry of SN1 reaction?a.retention of configuration at the electrophilic centerb.50:50 mixture of retention and inversion of configuration at the electrophilic centerc.inversion of configuration at the electrophilic centerd. slightly more inversion than retention at the electrophilic centerMatch the questions with the correct descriptions below: Sn2, E2 E1cb Sn1, E1 (anti) E2, E1cb Sn1, E1 2 steps poor leaving group 2 carbons removed from a carbonyl group carbanion intermediate 3°>allylic, benzylic>2°>1°>CH₃ carbocation intermediate Ist order reaction (r=k[RX]) H-X anti no intermediate 2nd order reaction (r=k[RX][Nu]) polar aprotic solventFor each of the following reactions diagram the steps from the substrate to the product. For each step, a) over the reaction arrow supply the needed reagents b) name the type of reaction/mechanism {ROS (SN1, SN2, radical) E(E1, E2) A [acid-base, addition (carbocation, onium bridge, radical)]}