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The technician then plates 0.1mL of the last three dilutions in duplicate. Why are the last three dilutions plated, as opposed to only one dilution? Why are the dilutions plated in duplicate?
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- Standardization of Sodium Thiosulfate Solution Primary Standard used: Potassium Dichromate Formula mass of 1o standard: __________________ % Purity of 1o standard: 99.80% Trials 1 2 3 Weight of K2Cr2O7 (g)Weight of K2Cr2O7 (g) 0.0315 0.0331 0.0380 Final Volume Reading Na2S2O3 (ml) 27.50 27.50 34.90 Initial Volume Reading Na2S2O3 (ml) 1.10 0.00 1.00 Net Volume Na2S2O3 used (ml) Molarity of Na2S2O3The gravimetric factor used to express CoCBr6·H20 in a sample that is finally weighed as PbClBr is choose below: FW PbClBr / 6 x FW CoCBr6·H20 FW CoCBr6·H20 / FW PbClBr FW CoCBr6·H20 / 6 x FW PbClBr 6 x FW PbClBr / FW CoCBr6·H20Standard deviation- 0.0371 mL, 0.0392 mL, 0.0392 mL, 0.03887 mL, 0.0398 mL Mean- 0.194 mL
- What weight of mercury bichloride should be taken as sample, assuming 100% purity, so that 0.5 g og HgS will be obtained in a gravimetric analysis? Gravimetric factor = 1.1669I would need help with these questions. The method referenced above was followed by a student and she got the following results: Caffeine Std. Conc. (ppm) Absorbance 100 1.806 50 0.899 40 0.724 30 0.545 20 0.365 10 0.183 Further, she analyzed an unknown sample and she got the following results: Sample # Absorbance 1 0.398 1. Graphically find the concentration in ppm and then calculate in mol/L of Caffeine in Sample #1? 2. Which solvent was used to extract Caffeine and why? Why is it necessary to do extraction three times? 3. Cuvettes used in this experiment were made from which material and why? 4. At what wavelength the Absorbance was measured?To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different. Location 1 standard deviation: 0.050 Location 2 standard deviation: 0.34 What is the calculated ? value for comparing the standard deviations?
- y= mx+ b Slope () = -4E-09 y-intercept () = 0.4021 and OD= 0.540 , Calculate the concentration (x)Concentration of AR Stock Solution (ppmppm) 21.22 Unrounded Rounded Concentration of AR Stock Solution (μMμM) 42.7461 42.7Standard deviation 0.6318 mL, 0.1216 mL, 0.1056 mL, 0.0681 mL, 0.0056 mL Mean-0.18654 mL
- To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different. Location 1 Standard deviation = 0.050 Location 2 standard deviation = 0.34 a) What is the calculated ? value for comparing the standard deviations? Fcalc = __________________If a patient added a 17-g measured dose of polyethylene glycol 3350 (miralax) to 180 mL of water to use as a laxative. If the given volume of the resultant mixture was 195.6 mL. Now, determine the apparent density of polyethylene glycol 3350 and the specific gravity of the mixture.Measurements of boiling temperatures of samples of a liquid (°C) are given below: 78.4 79.0 78.8 79.2 78.6 Calculate the meanCalculate the modeCalculate the standard deviation