With given information posted in photos, what is  a. The pulse rate mean and standard deviation for the population, what is the z score of someone with a pulse of 92 b. Explain the z score generated. Where does it lie? c. What is the pulse of a subject with a z score of -.6

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With given information posted in photos, what is 

a. The pulse rate mean and standard deviation for the population, what is the z score of someone with a pulse of 92

b. Explain the z score generated. Where does it lie?

c. What is the pulse of a subject with a z score of -.6 

11:05 7
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Math / Statistics / Q&A Library / ulse of people older t.…..
ulse of people older than 70 populati...
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Step 1
Given:
opulation mean = (u = 80)
%3D
standard deviation (o = 5)
Smaple size (n) = 20
Step 2
Transcribed Image Text:11:05 7 ll LTE D AA A bartleby.com = bartleby Q&A Math / Statistics / Q&A Library / ulse of people older t.….. ulse of people older than 70 populati... Get live help whenever you Try bartleby tutor today need from online tutors! Step 1 Given: opulation mean = (u = 80) %3D standard deviation (o = 5) Smaple size (n) = 20 Step 2
11:05 7
ll LTE D
AA
A bartleby.com
= bartleby
Q&A IO
Math / Statistics / Q&A Library / ulse of people older t.…..
ulse of people older than 70 populati...
Get live help whenever you Try bartleby
tutor today
need from online tutors!
Step 2
As the population standard deviation is known,
it can be said that the distribution follows
normal distribution. The mean and standard
deviation of the sampling distribution of the
sample mean is equal to ux and
respectively.
oz = ol yn
For this case, the mean will be 80 and the
standard deviation will be,
ol yn
/20
V5
1. 11803
~ 1. 118
Transcribed Image Text:11:05 7 ll LTE D AA A bartleby.com = bartleby Q&A IO Math / Statistics / Q&A Library / ulse of people older t.….. ulse of people older than 70 populati... Get live help whenever you Try bartleby tutor today need from online tutors! Step 2 As the population standard deviation is known, it can be said that the distribution follows normal distribution. The mean and standard deviation of the sampling distribution of the sample mean is equal to ux and respectively. oz = ol yn For this case, the mean will be 80 and the standard deviation will be, ol yn /20 V5 1. 11803 ~ 1. 118
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