Without adding any method or function to the classes shown below. Find out the coverage of the canvas that encloses all the circles that are generated by the program. Circle 0: center = (x = 35.57, y = -36.60), radius = 92.27 Circle 1: center = (x = -18.04, y = -5.67), radius = 98.76 Circle 2: center = (x = -10.82, y = -45.88), radius = 111.03 Circle 3: center = (x = 48.97, y = 1.55), radius = 106.70 Circle 4: center = (x = -12.89, y = 4.64), radius = 86.49 Circle 5: center = (x = 19.07, y = 17.01), radius = 145.67 Circle 6: center = (x = 15.98, y = 12.89), radius = 139.18 Circle 7: center = (x = -3.61, y = -9.79), radius = 85.05 Circle 8: center = (x = -8.76, y = 44.85), radius = 98.76 Circle 9: center = (x = -39.69, y = -28.35), radius = 127.63 Circle 1 intersecting with Circle 4, 5, 6 Circle 3 intersecting with Circle 5 Circle 4 intersecting with Circle 5, 6 Circle 5 intersecting with Circle 6, 7, 8 Circle 6 intersecting with Circle 7 Circle 7 intersecting with Circle 9 Bye... Note that intersection display of circle i and j is based on the condition of i < j. You can submit up to two times. Use seed 123 for your submission.   #include #include #include #include #include #include #include using namespace std; class Point { // cannot modify    double m_x;    double m_y; public:    Point(const double a, const double b) : m_x(a), m_y(b) {}    double x() const { return m_x; }    double y() const { return m_y; }    friend ostream& operator<<(ostream&, const Point&); }; class Circle { // cannot modify    int id;    Point center;    double radius; public:    Circle(const int n, const Point& p, const double r) : id(n), center(p), radius(r) {}    bool operator<(const Circle&) const;    friend ostream& operator<<(ostream&, const Circle&); }; double uniform(const double a, const double b) {    assert(a < b);    return a + (b - a) / 97. * (rand() % 98); } int main() {    vector v;    for (int i = 0; i < 10; ++i) v.push_back(Circle(i, Point(uniform(-50, 50), uniform(-50, 50)), uniform(80, 150)));    for (int i = 0; i < 10; ++i) cout << v.at(i) << endl;    cout << "Bye..." << endl;    return 0; } expected output: Circle 0: center = (x = 35.57, y = -36.60), radius = 92.27 Circle 1: center = (x = -18.04, y = -5.67), radius = 98.76 Circle 2: center = (x = -10.82, y = -45.88), radius = 111.03 Circle 3: center = (x = 48.97, y = 1.55), radius = 106.70 Circle 4: center = (x = -12.89, y = 4.64), radius = 86.49 Circle 5: center = (x = 19.07, y = 17.01), radius = 145.67 Circle 6: center = (x = 15.98, y = 12.89), radius = 139.18 Circle 7: center = (x = -3.61, y = -9.79), radius = 85.05 Circle 8: center = (x = -8.76, y = 44.85), radius = 98.76 Circle 9: center = (x = -39.69, y = -28.35), radius = 127.63 Circle 1 intersecting with Circle 4, 5, 6 Circle 3 intersecting with Circle 5 Circle 4 intersecting with Circle 5, 6 Circle 5 intersecting with Circle 6, 7, 8 Circle 6 intersecting with Circle 7 Circle 7 intersecting with Circle 9 Bye

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Without adding any method or function to the classes shown below. Find out the coverage of the canvas that encloses all the circles that are generated by the program.

Circle 0: center = (x = 35.57, y = -36.60), radius = 92.27 Circle 1: center = (x = -18.04, y = -5.67), radius = 98.76 Circle 2: center = (x = -10.82, y = -45.88), radius = 111.03 Circle 3: center = (x = 48.97, y = 1.55), radius = 106.70 Circle 4: center = (x = -12.89, y = 4.64), radius = 86.49 Circle 5: center = (x = 19.07, y = 17.01), radius = 145.67 Circle 6: center = (x = 15.98, y = 12.89), radius = 139.18 Circle 7: center = (x = -3.61, y = -9.79), radius = 85.05 Circle 8: center = (x = -8.76, y = 44.85), radius = 98.76 Circle 9: center = (x = -39.69, y = -28.35), radius = 127.63 Circle 1 intersecting with Circle 4, 5, 6 Circle 3 intersecting with Circle 5 Circle 4 intersecting with Circle 5, 6 Circle 5 intersecting with Circle 6, 7, 8 Circle 6 intersecting with Circle 7 Circle 7 intersecting with Circle 9 Bye...

Note that intersection display of circle i and j is based on the condition of i < j. You can submit up to two times. Use seed 123 for your submission.

 

#include <iostream>
#include <cstdlib>
#include <iomanip>
#include <vector>
#include <algorithm>
#include <cmath>
#include <cassert>
using namespace std;

class Point { // cannot modify
   double m_x;
   double m_y;
public:
   Point(const double a, const double b) : m_x(a), m_y(b) {}
   double x() const { return m_x; }
   double y() const { return m_y; }
   friend ostream& operator<<(ostream&, const Point&);
};

class Circle { // cannot modify
   int id;
   Point center;
   double radius;
public:
   Circle(const int n, const Point& p, const double r) : id(n), center(p), radius(r) {}
   bool operator<(const Circle&) const;
   friend ostream& operator<<(ostream&, const Circle&);
};

double uniform(const double a, const double b) {
   assert(a < b);
   return a + (b - a) / 97. * (rand() % 98);
}

int main() {
   vector<Circle> v;
   for (int i = 0; i < 10; ++i) v.push_back(Circle(i, Point(uniform(-50, 50), uniform(-50, 50)), uniform(80, 150)));
   for (int i = 0; i < 10; ++i) cout << v.at(i) << endl;
   cout << "Bye..." << endl;
   return 0;
}

expected output:

Circle 0: center = (x = 35.57, y = -36.60), radius = 92.27 Circle 1: center = (x = -18.04, y = -5.67), radius = 98.76 Circle 2: center = (x = -10.82, y = -45.88), radius = 111.03 Circle 3: center = (x = 48.97, y = 1.55), radius = 106.70 Circle 4: center = (x = -12.89, y = 4.64), radius = 86.49 Circle 5: center = (x = 19.07, y = 17.01), radius = 145.67 Circle 6: center = (x = 15.98, y = 12.89), radius = 139.18 Circle 7: center = (x = -3.61, y = -9.79), radius = 85.05 Circle 8: center = (x = -8.76, y = 44.85), radius = 98.76 Circle 9: center = (x = -39.69, y = -28.35), radius = 127.63 Circle 1 intersecting with Circle 4, 5, 6 Circle 3 intersecting with Circle 5 Circle 4 intersecting with Circle 5, 6 Circle 5 intersecting with Circle 6, 7, 8 Circle 6 intersecting with Circle 7 Circle 7 intersecting with Circle 9 Bye...

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