wn, at which the spring is unstretched. How far will the 3.0 -rsed?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter7: Conservation Of Energy
Section: Chapter Questions
Problem 15P: A block of mass m = 2.00 kg is attached to a spring of force constant k = 500 N/m as shown in Figure...
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A block of mass 2.0 kg is hung from a spring, causing it to stretch 12 cm at equilibrium, as shown.
The 2.0 kg block is then replaced by a 3.0 kg block, and the new block is released from the position
shown, at which the spring is unstretched. How far will the 3.0 kg block fall before its direction is
reversed?
12
а) 12 сm
b)24 cm
c) 36 cm
d) 48 cm
e)none of the above
Transcribed Image Text:A block of mass 2.0 kg is hung from a spring, causing it to stretch 12 cm at equilibrium, as shown. The 2.0 kg block is then replaced by a 3.0 kg block, and the new block is released from the position shown, at which the spring is unstretched. How far will the 3.0 kg block fall before its direction is reversed? 12 а) 12 сm b)24 cm c) 36 cm d) 48 cm e)none of the above
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I have another solution using energy conservation where the gravitational potential energy is converted to elastic potential energy and the stretch that I get is different than what you calculate. I get 36 cm for my answer. Which method is correct? I would have done it your way and the answers should be the same I would think? 

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