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- Write a method that will receive 3 integers and return the largest integer. public static int findMax(int a, int b, int c) {write a method that calculate the average of all numbers from 1 to n, return a double valueWrite a method that returns the sum of a range of numbers. It should take the starting and ending numbers of the range (inclusive) as parameters. (Use Java) For example: sumRange(0, 5) // returns 15 (0 + 1 + 2 + 3 + 4 + 5 = 15)sumRange(3,10) // returns 55 (3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 52)sumRange(5, 7) // returns 18 (5 + 6 + 7 = 18)
- For this problem you will write a method that prints out a pyramid. The boxes in each layer of the pyramid are stacked directly on top of one another (i.e. not offset between two boxes below). For example, below are shown two pyramids, one with base 5 and one with base 6. [] [][] [][][] [][][][] [][][][][] [][][][][][]Write a java method sumOfAllOddNumbersBetween() that takes as input two integers and returns the sum of all odd numbers that are between the two given numbers (the given numbers should be excluded from the sum). Write a main program to test your method by accepting the two integers from the user.Write a method called min that takes three integers as parameters and returns the smallest of the three values; for example, a call of min(3,–2, 7) would return 22, and a call of min(19, 27, 6) would return 6. Use Math.min to write your solution.
- *in java* Write a method printShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, print "Too few.". If more than 4, print "Too many.". Else, print "N: Lather and rinse." numCycles times, where N is the cycle number, followed by "Done.". End with a newline. Example output with input 2: 1: Lather and rinse. 2: Lather and rinse. Done. Hint: Declare and use a loop variable. import java.util.Scanner; public class ShampooMethod { /* Your solution goes here */ public static void main (String [] args) {Scanner scnr = new Scanner(System.in);int userCycles; userCycles = scnr.nextInt();printShampooInstructions(userCycles);}}Write a Java method that generates and returns a random number between 2 valuesreceived as parameters. You must consider 2 cases when there are or not differencebetween values (please refer to slide 43 from 04 Methods). The function should checkif the difference is strictly positive otherwise replace it with the value 1.Test your method using main as follows (bold values are input by the user):Lowest value: 60Highest value: 100Diff. between values: 5Number of random numbers: 5060 90 70 65 70 60 75 100 100 8580 90 60 95 75 65 80 70 90 9085 65 95 60 85 95 75 85 60 7090 80 65 65 90 90 80 60 95 7560 90 70 70 90 60 65 60 85 60Define a method findEmployeeTax() that takes two integer parameters as a person's salary and the number of dependents, and returns the person's tax percent as a double. The tax percent is returned as follows: Salary ≤ 1 dependent 2 - 5 dependents ≥ 6 dependents < 450000 0.15 0.05 0 450000 - 824999 0.25 0.15 0.15 ≥ 825000 0.4 0.25 0.25 Ex: If the input is 425000 0, then the output is: 0.15 import java.util.Scanner; public class TaxFinder { public static double findEmployeeTax(int salary, int numDepen) { double i; if (salary < 450000) { if(numDepen <= 1) i = 0.15; else if (numDepen >= 2 && numDepen <= 5) i = 0.05; else if (numDepen >= 6) i = 0; } else if (salary >= 450000 && salary <= 824999) { if(numDepen <= 1) i = 0.25; else if (numDepen >= 2 && numDepen <= 5) i = 0.15; else if (numDepen >= 6) i = 0.15; } else if…
- Write a Java program that implements static method roundSum() so that given 3 ints: a, b, and c; return the sum of their rounded values. We'll round an int value up to the next multiple of 10 if its rightmost digit is 5 or more, so 15 rounds up to 20. Alternately, round down to the previous multiple of 10 if its rightmost digit is less than 5, so 12 rounds down to 10. roundSum(16, 17, 18) → 50roundSum(12, 13, 14) → 40roundSum(6, 4, 4) → 10 The examples of input and output you can see in the picture. (the code structure should be as in the second picture)Write a java method named findLargest that returns the largest number stored in it's parameter, an array of int value.Write a method printShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, print "Too few.". If more than 4, print "Too many.". Else, print "N: Lather and rinse." numCycles times, where N is the cycle number, followed by "Done.". End with a newline. Example output with input 2: 1: Lather and rinse. 2: Lather and rinse. Done. import java.util.Scanner; public class ShampooMethod { /* Your solution goes here */ public static void main (String [] args) {Scanner scnr = new Scanner(System.in);int userCycles; userCycles = scnr.nextInt();printShampooInstructions(userCycles);}}