Write a recursive function for printing n box shapes [ ] in a row. Hint: Print one [], then print n - 1 of them. Complete the following file: boxes.cpp 1 #include 2 using namespace std; 3 4 void print_boxes(int n) 5 { if (. . .) { . ; } 7 cout << 8 print_boxes(. .);| 9.
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![Write a recursive function for printing n box shapes [ ] in a row.
Hint: Print one [], then print n - 1 of them.
Complete the following file:
boxes.cpp
1 #include <iostream>
2 using namespace std;
3
4 void print_boxes(int n)
5 {
6.
if (. . .) { .
cout <<
; }
7
8
print_boxes(. . .);|
9 }](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe2932faa-b49a-4196-8420-f277821525a8%2Fb2a4688e-5820-4ee2-bd20-3b6464c10e81%2Fvb8k5dp_processed.png&w=3840&q=75)
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- Write a recursive Java function displayOutIn that displays two items from an array list at one instance from out-to-in. until one or last two items displayed and the process stops. For example, given array A = {15, 74, 106, 10, 9, 86, 34} the displayOutIn function displays the following: 15, 34 74, 86 106, 9 10Write a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below. def count_ordered ( seq ) : """ Input : A sequence of comparable elements Output : The number of elements that are less than the following element in the sequence Example : >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] ) 5 >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) ) 2 >>> count_ordered ( 'Python' ) 2 >>> count_ordered ( [ 6 ] ) 0 >>> count_ordered ( [ ] ) 0 """ In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…Write a RECURSIVE function, without using any loops, that prints the contents of a matrix with 3 columns. The function should take the matrix and the number of rows as arguments. void print_matrix(int arr[][3], int num_rows);
- in C programing Write a recursive function that returns 1 if an array of size n is in sorted order and 0 otherwise. Note: If array a stores 3, 6, 7, 7, 12, then isSorted(a, 5) should return 1 . If array b stores 3, 4, 9, 8, then isSorted(b,4) should return 0.int isSorted(int *array, int n){Write a recursive function named reverseWithinBounds that has an argument that is an array of characters and two arguments that are bounds on array indices. The function should reverse the order of those entries in the array whose indices are between the two bounds (including the bounds). For example, if the array is: a[0] == 'A' a[1] == 'B' a[2] == 'C' a[3] == 'D' a[4] == 'E' and the bounds are 1 and 4, then after the function is run the array elements should be: a[0] == 'A' a[1] == 'E' a[2] == 'D' a[3] == 'C' a[4] == 'B' Embed the function in a program and test it. After you have fully debugged this function, define another function named reverseCstring that takes a single argument that is a C string and modifies the argument so that it is reversed. This function will include a call to the recursive definition you did for the first part of this project, and need not be recursive. Embed this second function in a program and test it.Write a recursive function named reverseWithinBounds that has an argument that is an array of characters and two arguments that are bounds on array indices. The function should reverse the order of those entries in the array whose indices are between the two bounds (including the bounds). For example, if the array is: a[0] == 'A' a[1] == 'B' a[2] == 'C' a[3] == 'D' a[4] == 'E' and the bounds are 1 and 4, then after the function is run the array elements should be: a[0] == 'A' a[1] == 'E' a[2] == 'D' a[3] == 'C' a[4] == 'B' Embed the function in a program and test it. After you have fully debugged this function, define another function named reverseCstring that takes a single argument that is a C string and modifies the argument so that it is reversed. This function will include a call to the recursive definition you did for the first part of this project, and need not be recursive. Embed this second function in a program and test it. Turn in only this final result (with output,…
- Write a recursive function named reverseWithinBounds that has an argument that is an array of characters and two arguments that are bounds on array indices. The function should reverse the order of those entries in the array whose indices are between the two bounds (including the bounds). For example, if the array is: a[0] == 'A' a[1] == 'B' a[2] == 'C' a[3] == 'D' a[4] == 'E' and the bounds are 1 and 4, then after the function is run the array elements should be: a[0] == 'A' a[1] == 'E' a[2] == 'D' a[3] == 'C' a[4] == 'B'For function decToBinary, write the missing parts of the recursion case. This function should return a string that stores the binary equivalent for int variable num. Example: The binary equivalent of 13 may be found by repeatedly dividing 13 by 2. So, 13 in base 2 is represented by the string "1101". Examples: decToBinary(13) -> "1101" public String decToBinary (int num) { if (num < 2) return Integer.toString(num); else return <<Missing recursive call>> + <<Missing calculation>>;}In C++ Write a program that lists all ways people can line up for a photo (all permutations of a list of strings). The program will read a list of one word names (until -1), and use a recursive method to create and output all possible orderings of those names, one ordering per line. When the input is: Julia Lucas Mia -1 hen the output is (must match the below ordering): Julia Lucas Mia Julia Mia Lucas Lucas Julia Mia Lucas Mia Julia Mia Julia Lucas Mia Lucas Julia #include <vector>#include <string>#include <iostream> using namespace std; // TODO: Write method to create and output all permutations of the list of names.void AllPermutations(const vector<string> &permList, const vector<string> &nameList) { } int main(int argc, char* argv[]) { vector<string> nameList; vector<string> permList; string name; // TODO: Read in a list of names; stop when -1 is read. Then call recursive method. return 0;}
- Write a function in a racket code that takes as input a list of elements and returns a list with elements and their position after. For example, if the input to the function is (list ’a ’b ’c) then it will return (list a 1 b 2 c 3). Make sure to use recursion/** * Write a Java function to determine if the elements of an array can be split into two groups such that the sum of one group is a non-zero multiple of 10 and the sum of the other group is odd. Your solution must use recursive backtracking. <code> * Example: * Given: {1, 2, 6, 3, 1} * Result: true because {1,2,6,1}, {3} is one possibility. * * Example: * Given: {4, 3, 5, 2} * Result: false * </code> */ public static boolean splitOdd10(int[] num) { }A palindrome is a sentence that contains the same sequence of letters reading it either forwards or backwards. A classic example is '1\.ble was I, ereI saw Elba." Write a recursive function that detects whether a string is apalindrome. The basic idea is to check that the first and last letters of thestring are the same letter; if they are, then the entire string is a palindromeif everything between those letters is a palindrome.There are a couple of special cases to check for. If either the first orlast character of the string is not a letter, you can check to see if the restof the string is a palindrome with that character removed. Also, when youcompare letters, make sure that you do it in a case-insensitive way.Use your function in a program that prompts a user for a phrase andthen tells whether or not it is a palindrome. Here's another classic fortesting: '1\. man, a plan, a canal, Panama!"